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Goshia [24]
3 years ago
6

How would you describe the motion of plates in a collision zone?

Chemistry
1 answer:
Gennadij [26K]3 years ago
7 0

Explanation:

The plates move INTO each other in a convergent boundary causing a collision. As the plates collide, the denser plate becomes subducted under the less dense plate. There is enormous stress between the two plates as they move past each other. This stress from the friction causes the plates to warp at the boundary. The geographical feature formed at such a boundary is the mid-ocean trench- along the boundary.

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1. How many grams of NaOH are in 400.0 mL of a 0.5 M solution of NaOH?
Anit [1.1K]
1. molarity = (moles)/vol in litres
0.5=[(weight/40)*1000]/4
0.5 = weight/16
weight of NaOH = 8 grams

2. weight = 0.45*850*84/100 gms
molecular weight = 85m (not sure abt this)
3 0
3 years ago
The formula for a buffer solution contains 1.24% w/v of boric acid. How many milliliters of a 5% w/v boric acid solution should
Yanka [14]

Answer:

248 mL of 5% w/v boric acid solution should be used to obtain the solution needed.

 

Explanation:

We can calculate the volume of the 5% w/v boric acid solution needed to prepare the buffer solution 1.24% w/v using the following equation:

C_{i}V_{i} = C_{f}V_{f}

Where:

C_{i}: is the concentration of the initial solution = 5% w/v

C_{f}: is the concentration of the final solution = 1.24% w/v

V_{i}: is the volume of the initial solution =?

V_{f}: is the volume of the final solution = 1 L

Hence, the volume of the 5% solution is:

V_{i} = \frac{C_{f}V_{f}}{C_{i}} = \frac{1.24 \%*1 L}{5 \%} = 0.248 L = 248 mL

Therefore, 248 mL of 5% w/v boric acid solution should be used to obtain the solution needed.

I hope it helps you!                  

6 0
3 years ago
0.0000062 kg in scientific notation
slava [35]

Answer:

6.2 x 10^{-6}

Explanation:

You are moving the decimal point six spots to the right.

8 0
2 years ago
Which solid will be more soluble in water, the one with the larger lattice energy or the one with the smaller lattice energy? as
grandymaker [24]
Lattice energy is the amount of energy expelled when the solid is disintegrated into ions. For example, the solid is Sodium Chloride. In ionic form, that would consist of sodium and chlorine ions.The solid with a smaller lattice energy would be easily disrupted, hence, when a solvent is incorporated, the solid becomes solvated ions.
7 0
4 years ago
When of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing poi
Nesterboy [21]

The given question is incomplete. The complete question is:

When 282. g of glycine (C2H5NO2) are dissolved in 950. g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 282. g of ammonium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X.

Answer:  the van't Hoff factor for ammonium chloride is 1.74

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point  

K_f = freezing point constant = ?

i = 1 ( for non electrolyte)

m= molality

8.2^0C=1\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (glycine) = 75.07 g/mol

Mass of solute (glycine) = 282 g

8.2^0C=1\times K_f\times \frac{282g}{75.07g/mol\times 0.95kg}

K_f=2.07

ii) 20.0^0C=i\times \times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (ammonium chloride) = 53.49 g/mol

Mass of solute (ammonium chloride) = 282 g

20.0^0C=i\times 2.07\times \frac{282g}{53.49g/mol\times 0.95kg}

i=1.74

Thus the van't Hoff factor for ammonium chloride is 1.74

4 0
3 years ago
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