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Mrrafil [7]
3 years ago
8

A molecule has four bonded atoms around a central atom. The central atom does not have any lone pairs of electrons. What is the

geometry of the molecule?
Bent
Linear
Trigonal planar
Tetrahedral
Chemistry
2 answers:
lozanna [386]3 years ago
6 0

Answer:

Tetrahedral

Explanation:

A molecule has four bonded atoms around a central atom. The central atom does not have any lone pairs of electrons. An example is CCl4, here the central C atom has 4 valence electrons, and the C makes a covalent bond with each of the four Cl atoms. In a C-Cl covalent bond an electron pair is shared. After fur C-Cl bonds C is left with no valence electron, hence there are no lone pair of electrons on C. Each of the four C-Cl bonds is directed towards the four corners of a tetrahedron.

iren [92.7K]3 years ago
5 0
Tetrahedral. like methan ch4 it doesn t have lone pairs of electrons and the bonds are oriented with a 109* 28' angle and a tetrahedron has the angles of 109 degrees so almost the same.
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Given the standard enthalpy changes for the following two reactions: (1) 2Fe(s) + O2(g)2FeO(s)...... ΔH° = -544.0 kJ (2) 2Zn(s)
Keith_Richards [23]

Answer:

-76.3 kJ

Explanation:

Here is the complete question

Given the standard enthalpy changes for the following two reactions:

(1) 2Fe(s) + O₂(g) → 2FeO(s)......ΔH° = -544.0 kJ

(2) 2Zn(s) + O₂(g) → 2ZnO(s)......ΔH° = -696.6 kJ. What is the standard enthalpy change for the reaction:

(3) FeO(s) + Zn(s) → Fe(s) + ZnO(s)......ΔH° = ?

Solution

Since (1) 2Fe(s) + O₂(g) → 2FeO(s)......ΔH° = -544.0 kJ

reversing the reaction, we have

2FeO(s) → 2Fe(s) + O₂(g) ......ΔH° = +544.0 kJ (4)

Adding reactions (2) and (3), we have

2FeO(s) → 2Fe(s) + O₂(g) ......ΔH° = +544.0 kJ (4)

2Zn(s) + O₂(g) → 2ZnO(s)......ΔH° = -696.6 kJ  (2)

This gives

2FeO(s) + 2Zn(s) → 2Fe(s) + 2ZnO(s)......ΔH° =

The enthalpy change for this reaction is the sum of enthalpy changes for reaction (2) and (3) = ΔH° = +544.0 kJ + (-696.6 kJ)

= +544.0 kJ - 696.6 kJ)

= -152.6 kJ

Since the required reaction is (3) which is FeO(s) + Zn(s) → Fe(s) + ZnO(s)

we divide the enthalpy change for reaction (4) by 2 to obtain the enthalpy change for reaction (3).

So, ΔH° = -152.6 kJ/2 = -76.3 kJ

So, the standard enthalpy change for the reaction

FeO(s) + Zn(s) → Fe(s) + ZnO(s) is -76.3 kJ

8 0
3 years ago
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zaharov [31]

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

<h3>What is ionization energy?</h3>

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

  • E_n = \frac{E_0 × Z^{2}}{n^{2}}

where

E_0  \: is  \: ground  \: state  \: energy  \: of \:  hydrogen \:  atom \:  = -13.6 eV \\

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substituting the values:

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Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: brainly.com/question/1445179

5 0
2 years ago
Convert this temperature from F to C<br><br> 26.6°c<br> 93.600<br> 62.2°C<br> 5.7°C
eduard
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3 years ago
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telo118 [61]

Answer:

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Explanation:

There are also sulfur dioxide, or sulfur trioxide, which is usually used in the formation of tertiary salts such as copper sulfate.

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