The scientific models are used because they allow scientists to make predictions and make it easier for scientists to avoid using data. option A and C is correct.
<h3>What are scientific models?</h3>
The scientific models are those which is given by scientists to allow them to make prediction about anything particular on which they are working or making research for it some examples are plum pudding model for an atom and bohr's model of an atom etc.
The biggest advantage is that scientists do not have to check the given data which are written into books they can perform their experiment and can conclude the data by performing experiment.
Therefore, scientific models are used because they allow scientists to make predictions and make it easier for scientists to avoid using data. option A and C is correct.
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<u><em>Answer:</em></u>
- The correct answer is a.
- The ratio of their masses is always the same
<u><em>Explanation:</em></u>
- Dalton law was based on law of conservation of masses and law of conservation definite proportional. So here , it is cleared that the ratio of their masses should be always same.
Answer:
c) Seasonal migration
Explanation:
Because A, B and C are all examples of structural adaptations. And seasonal migration is not something that is in an animals structure but is instinct.
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Answer:
0.00235
Explanation:
- Zeros that come before any non-zero digits are never significant.
- Zeros that are in between any non-zero digits are always significant.
- Zeros that come after any non-zero digit are ONLY significant if a decimal point in present somewhere in the number. (In this case there is a decimal point, but there aren't any zeros at the end of this number.)
The zeros at the beginning aren't significant, so include those zeros in your answer. The 6 at the end in greater than 5 so that rounds the 4 to up one number (In this case, it's 5).
This gives you 0.00235
Answer:
1.195 M.
Explanation:
- We can calculate the concentration of the stock solution using the relation:
<em>M = (10Pd)/(molar mass).</em>
Where, M is the molarity of H₂SO₄.
P is the percent of H₂SO₄ (P = 40%).
d is the density of H₂SO₄ (d = 1.17 g/mL).
molar mass of H₂SO₄ = 98 g/mol.
∴ M of stock H₂SO₄ = (10Pd)/(molar mass) = (10)(40%)(1.17 g/mL) / (98 g/mol) = 4.78 M.
- We have the role that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.
<em>∴ (MV) before dilution = (MV) after dilution</em>
M before dilution = 4.78 M, V before dilution = 250 mL.
M after dilution = ??? M, V after dilution = 1.0 L = 1000 mL.
∴ M after dilution = (MV) before dilution/(V after dilution) = (4.78 M)(250 mL)/(1000 mL) = 1.195 M.
