We have:
Event A ⇒ P(A) = 0.16
Event B ⇒ P(B) = 0.09
Probability of event B given event A happening, P(B|A) = P(A∩B) / P(A) = 0.12
By the conditional probability, the probability of event A and event B happens together is given by:
P(B|A) = P(A∩B) ÷ P(A)
P(B|A) = P(A∩B) ÷ 0.16
0.12 = P(A∩B) ÷ 0.16
P(A∩B) = 0.12 × 0.16
P(A∩B) = 0.0192
When two events are independent, P(A) × P(B) = P(A∩B) so if P(A∩B) = 0.0192, then P(B) will be 0.0192 ÷ 0.16 = 0.12 (which take us back to P(B|A))
Since P(B|A) does not equal to P(B), event A and event B are not independent.
Answer: <span>Events A and B are not independent because P(B|A) ≠ P(B)</span>
Answer:
(5m^3+4)(5m^3-4)
Step-by-step explanation:
(*) A^2 - B^2 =(A+B) (A-B)
25m^6-16=
(5m^3)^2 - 4^2=(*)
(5m^3+4)(5m^3-4)
Answer:
6.58 x 10^-3
Explanation:
Moving the decimal place till it’s in front of the 6
The 7 is moved around the edge
1.8(14)+25=50
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