Question

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Answer 1

Answer:

$96units^2$

Step-by-step explanation:

The total surface area of a cube is given by $6l^2$.

The first cube has side length $l=6$ units.

This cube has total surface area, $6(6)^2=216units^2$.

If the second cube is reduced in size by $\frac{2}{3}$, then the corresponding change in area is $\frac{2^2}{3^2}=\frac{4}{9}$.

the total surface area of the new cube is $=\frac{4}{9}\times 216$.

$=96units^2$

Answer 2

Answer:

Step-by-step explanation: