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Marta_Voda [28]
3 years ago
5

Need help with this question

Mathematics
2 answers:
Keith_Richards [23]3 years ago
8 0
Y=-1/3x+5 because were the y axis is at is the 5 and u go up one to the right 3 to reach ur next point
slavikrds [6]3 years ago
5 0
Y= mx + b is the form of slope

b also is y-intercept
So the y-intercept is always on y-axis
You can see that the line fall on number 5 so
Y=mx + 5

Mx is the slope want to find the slope the form is
Y2 -y1 / x2-x1

For example (0,5) and (6,3)

3-5 = -2

6-0 = 6

-2/6 = -1/3

Y= -1/3 +5
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Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: between the midpoints of segments AP and QB
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Answer:

\frac{a}{8}

Step-by-step explanation:

AB = a

AP = 2PQ = 2QB

AB = AP + PQ + QB

     = AP + \frac{AP}{2} + \frac{AP}{2}

AB = 2AP

AP = \frac{a}{2} -----(1)

And we know QB = \frac{AP}{2}

QB= AP/2 = \frac{a}{4} ---------(2)

Now midpoint of AP = \frac{a}{2} × \frac{1}{2} = \frac{a}{4}

and midpoint of QB = \frac{a}{4} × \frac{1}{2} = \frac{a}{8}

distance between these midpoints = \frac{a}{4} - \frac{a}{8}

= \frac{a}{8}

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