Hello from MrBillDoesMath!
Discussion:
The slope of the tangent to the curve y = 4x^3 is given by the first derivative.
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y' = 4 (3x^2) = 12x^2
At (-3,-108), the slope is 12x^2 = 12(-3)^2 = 12*9 = 108
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y = mx + b
From the first part, m = 108 so y = 108x + b.
Substituting y = -108 when x = -3 gives
-108 = 108(-3) + b => add 3* 108 to both sides
-108 + 108(3) = b => as 3 -1 = 2
108*2 = b = 216
y = 108x + 216
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Thank you,
MrB
Answer:
D.) Elliott has 212 cans, Amelia has 45 cans
Step-by-step explanation:
257 = x + (5x - 12)
257 = 6x - 13
+13 +13
270 = 6x
/6 /6
45 = x (the amount of Amelia's cans)
257 - 45 = 212 (the amount of Elliott's cans)
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The answer to the question
Answer:
A
Step-by-step explanation:
f(g(3)= f(g(x=3)) = f(
) = f(4/2) = f(2) = f(x=2) = 3*2-7 = 6-7 = -1
Using the slope-intercept form, the slope is 3 3 . To find an equation that is parallel<span>to </span>y=3x−2 y<span> = 3 x - </span>2<span> , the slopes must be equal. Using the slope of the equation, find the </span>parallel line<span> using the point-slope formula. Find the value of b b using the formula for the equation of a </span>line<span>.</span>