The correct answer is: [C]: "polar" .
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" Water " ; which is: " H₂O " ;
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is a:
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— polar; → {eliminate: "Choice [A]: "non-polar"} ;
→ {and consider: "Choice: [C]: "polar" } ;
— covalent; → {not "ionic"; eliminate: "Choice: [B]: "ionic"} ;
— uncharged; → {neutral compound; not "charged" —but "balanced"} ;
→ {Note: " H ⁺ , O ²⁻ ; → " H₂O " } ;
→ The "charges" balance/ cancel out.
→ {eliminate: "Choice: [D]: "charged" .}.
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— compound.
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The correct answer is: [C]: "polar" .
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Idk if this is of any help but if you multiply 8 cents times the 250 watts you get 20 then you multiply that but the 24 hrs you are going to be using it for and I got 480
Hello!
The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:
Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:
CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)
Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻
This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.
Have a nice day!
