<span>What did you observe?
When the mixture of Jell-O is shined with the light you observe that the mixture becomes opaque or misty.
In the other two glasses the mixture remains clear
The Jell-O mixture dispereses the light while the other two glasses let the light pass through them.
What is the Tyndall effect?
The Tyndall effect is the dispersion of light by colloid particles. This happens becasue colloid particles present in the mixture are bigger than solvated particles.
Colloid particles are so small that they cannot be in the mixture, but are big enough to disperse the light.
Which glass displayed the Tyndall effect?
The glass with the Jell-O displayed the Tyndall effect.
What does that tell you about the substance in the glass?
The mixture of this glass is a colloid, because they are the only mixtures that may look clear but becomes misty when the light passes trhough them.
Which glass represents a pure substance?
Only the glass with pure water represents a pure substance, one of the glasses that did not disperse the light.
Which glass represents a solution?
The other glass that did not disperse the light is a solution.
Pure substances and solutions do not disperese water. Diluted coloids look clear but disperse light.
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Answer:
B.
Explanation:
CO2 + H2 + O2 - are 3 individual substances.
Rays having a wavelength greater than 400 nm (such as visible, infrared, radio waves, etc.) do not cause damage to the cell.
Ultraviolet (UV) radiation is electromagnetic radiation with a wavelength between 100 and 400 nm.
Ionizing radiation such as X and gamma rays also have a small wavelength (less than that of UV rays), and can penetrate the cell and cause damage to the cell.
Answer:
Mass of C₂H₄N₂ produced = 3.64 g
Explanation:
The balanced chemical equation for the reaction is given below:
3CH₄ (g) + 5CO₂ (g) + 8NH₃ (g) → 4C₂H₄N₂ (g) + 10H₂O (g)
From the equation, 3 moles of CH₄ reacts with 5 moles of CO₂ and 8 moles of NH₃ to produce 4 moles of C₂H₄N₂ and 10 moles of H₂O
Molar masses of the compounds are given below below:
CH₄ = 16 g/mol; CO₂ = 44 g/mol; NH3 = 17 g/mol; C₂H₄N₂ = 56 g/mol; H₂O g/mol
Comparing the mole ratios of the reacting masses;
CH₄ = 1.65/16 = 0.103
CO₂ = 13.5/44 = 0.307
NH₃ = 2.21/17 = 0.130
converting to whole number ratios by dividing with the smallest ratio
CH₄ = 0.103/0.103 = 1
CO₂ = 0.307/0.103 = 3
NH₃ = 0.130/0.103 = 1.3
Multiplying through with 5
CH₄ = 1 × 5 = 5
CO₂ = 3 × 5 = 15
NH₃ = 1.3 × 5 = 6.5
Therefore, the limiting reactant is NH₃
8 × 17 g (136 g) of NH₃ reacts to produce 4 × 56 g (224 g) of C₂H₄N₂
Therefore, 2.21 g of NH₃ will produce (2.21 × 224)/136 g of C₂H₄N₂ = 3.64 g of C₂H₄N₂
Mass of C₂H₄N₂ produced = 3.64 g
The lone pairs on the oxygen in the following compound are best described as: <u>one localized and one delocalized</u>
<h3>Lone pair electron</h3>
A lone pair electron is valence shell electron pair associated with one atom, and not part of a covalent bond.
Within the context of this question, the oxygen atom of water for instance has two lone pair of which one of them is localized and other one is delocalized
Learn more about lone pair electrons:
brainly.com/question/3915115