<u>Answer:</u>
a. Oxidising agent: Cl₂
b. Reducing agent: NaBr
c. Oxidised: NaBr
d. Reduced: Cl₂
e. Oxidation numbers before reaction: Cl= 0, Na= +1, Br= -1
f. Oxidation numbers after reaction: Cl= -1, Na= +1, Br= 0
<u>Explanation:</u>
Oxidising agents reduces themselves, oxidising other elements/compounds.
Reducing agents oxidise themselves, reducing other elements/compounds.
Oxidation is the <u>loss</u> of electrons or an <u>increase</u> in oxidation number.
Reduction is the <u>gain</u> of electrons or <u>decrease</u> in oxidation number.
Find the molar mass of CH3 and divide that by 45.0. That should give a whole number and then mult that whole number by CH3 to find molecular formula to get like ( incorrect ex: C2H6) which is mult by 2
Answer:
Dunes are loose sand hills.
Loess is a compacted wind-blown formation of sediment.
Explanation:
Sand dunes are, as their name implies, made of sand which is itself made of tiny quartz pieces. Sand dunes are present where there is a ready source of broken down sandstone or other type of rock and wind to transport the sand. The dunes are mobile and loose and migrate over time.
Loess comes in vast formations and was created in a very different way. In the last ice age, winds from the north carried sediments loosened and ground by glaciers southwards. There, the sediments accumulated in large formations and became compacted over time.
Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.
Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.
Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.
Let the molar solubility be S upon dissociation.
PbBr₂ or Lead Bromide dissociates in pure water as follows:
PbBr₂ ----------> Pb⁺² + Br⁻
S 2S
Ksp = [Pb⁺²] [ Br⁻]
Ksp = (S) (2S)²
Ksp = 4S³
6.60 × 10⁻⁶ = 4S³
S = 0.0118M
Hence, the Molar solubility S is 0.0118M.
Learn more about Molar solubility here, brainly.com/question/16243859
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