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Vsevolod [243]
3 years ago
8

A sample of CO2 gas at 100 degrees Celsius has a volume of 250 mL at 760 mm Hg. How many moles of CO2 are present

Chemistry
1 answer:
Fed [463]3 years ago
6 0

There are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.

HOW TO CALCULATE NUMBER OF MOLES:

The number of moles of a sample of gas can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure of gas (atm)
  • V = volume (L)
  • n = number of moles (mol)
  • R = gas law constant (0.0821 Latm/molK)
  • T = temperature (K)

According to this question;

  • P = 760mmHg = 1 atm
  • T = 100°C = 100 + 273 = 373K
  • V = 250mL = 0.250L
  • n = ?

1 × 0.250 = n × 0.0821 × 373

0.250 = 30.62n

n = 0.250 ÷ 30.62

n = 8.16 × 10-³mol

Therefore, there are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.

Learn more about number of moles at: brainly.com/question/4147359

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So, this explains the answer.

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How can you make a supersaturated solution from a saturated solution?
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5 0
3 years ago
A compound that contains only carbon, hydrogen, and oxygen is 58.8% C and 9.87% H by mass. What is the empirical formula of this
Dmitry [639]

<u>Answer:</u> The empirical formula of the compound becomes C_5H_{10}O_2

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

Let the mass of the compound be 100 g

Given values:

% of C = 58.8%

% of H = 9.87%

% of O = [100 - 58.8 - 9.87] = 31.33%

Mass of C = 58.8 g

Mass of H = 9.87 g

Mass of O = 31.33 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of C}=\frac{58.8g}{12g/mol}=4.9 mol

\text{Moles of H}=\frac{9.87g}{1g/mol}=9.87 mol

\text{Moles of O}=\frac{31.33g}{16g/mol}=1.96mol

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 1.96 moles

\text{Mole fraction of C}=\frac{4.9}{1.96}=2.5

\text{Mole fraction of H}=\frac{9.87}{1.96}=5.03\approx 5

\text{Mole fraction of O}=\frac{1.96}{1.96}=1

Converting the mole fraction into whole numbers by multiplying them with 2.

\text{Mole fraction of C}=2.5\times 2=5

\text{Mole fraction of H}=5\times 2=10

\text{Mole fraction of O}=1\times 2=2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 5 : 10 : 2

Hence, the empirical formula of the compound becomes C_5H_{10}O_2

8 0
3 years ago
An atom of which element has the greatest attraction for electrons in a chemical bond
solniwko [45]
Se would be the answer I think. Hop this helped!
7 0
4 years ago
Read 2 more answers
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