Primarily, it detects peptidoglycan, which is present in a thick layer in Gram-positive bacteria. ... In Gram-positive bacteria, the cell wall is thick (15-80 nanometers), and consists of several layers of peptidoglycan. They lack the outer membrane envelope found in Gram-negative bacteria.
Link:https://courses.lumenlearning.com/boundless-microbiology/chapter/cell-walls-of-prokaryotes/
Note: This information has been taken out of a website.
Answer:
B. rr
Explanation:
Genotype- Is the genetic makeup of an organism.
An homozygous individual is one who has similar allele e.g AA
It could either be in dominant form(AA) or recessive form(aa)
An heterozygote individual has two different allele in its genotype e.g Aa
A dominant gene is a gene that expresses itself in the phenotype of an individual while a recessive gene is a gene that is not expressed in the phenotype.
The genotype for a white homozygous flower is WW while the genotype for homozygous recessive is ww.
The dominant genotype is usually denoted with capital letter and the recessive is denoted with small letter.
Answer:
1.875 is the expected number of children the couple will have.
Explanation:
<em>The probability of an event </em><em>X</em><em> is denoted by </em><em>P(X)</em><em>.</em>
Let assume that X is the number of children to whom the couple will give birth. The couple can have at most <em>four children</em> with the following probabilities.
- The couple will have one child if the first is boy, thus:
For one child P(X)=1/2=0.50
- The couple will have two children if the first is girl and the second is a boy, thus:
For two children P(X)=0.5×0.5=0.25
- The couple will have three children if the first two are girls and the third is a boy, thus:
For three children P(X)= 0.5×0.5×0.5=0.125
- The couple will have four children if the first three are girls and the fourth is a boy, or if all the four are girls. thus:
For four children P(X) =(0.5×0.5×0.5×0.5)+(0.5×0.5×0.5×0.5)=0.125
<u>Now calculating the expected number of children the couple will have:</u>
NOTE: Formula is given in the attached pic
Expected number of children = E(X)= (1×0.50)+(2×0.25)+(3×0.125)+(4×0.125)
E(X)= 1.875
Howdy howdy!
I think its FALSE.
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