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3 years ago

Elvira wants to predict how much her cable television service will cost each month. She pays a

Mathematics

1 answer:

lesya692 [45]3 years ago

8 0

Answer:

The answer is (C) Y = 69.99 + 4.99x

Step-by-step explanation:

x represents the number of movies ordered by Elvira.

69.99 is the constant Elvira has to pay for her cable service.

As we can see on the answer (C) the 4.99 is multiplied by x which represents the number of movies ordered by Elvira and she is charged 4.99 for each one so the logical thing to do is that we multiply 4.99 by x (number of movies ordered) then we add 69.99 to the product of 4.99x and we get the total amount Elvira has to pay this month

So the formula to find how much Elvira has to pay this month would be (C) y = 69.99 + 4.99x.

You might be interested in

Z varies jointly as x and y. z=60 when x=5 and y=6. find z when x = 7 and y=3

Aneli [31]

Answer:

z = 42

Step-by-step explanation:

The question can be answered in 2 steps as follows:

Step 1: Calculation of the constant of the variation

The equation for the joint variation can be given as follows:

z = cxy ................... (1)

Where;

z = 60

c = constant = ?

x = 5

y = 6

Substituting the values into equation (1) and solve c, we have:

60 = c * 5 * 6

60 = c * 30

c = 60 / 30

c = 2

Step 2: find z when x = 7 and y = 3

Since from Step 1 c = 2, we now use equation (1) and substitute the values into it to find z as follows:

z = 2 * 7 * 3

z = 42

4 0

3 years ago

Draw to show how you can use models to compare a 345 and 391

natali 33 [55]

345= 3 hundreds, 4 tens, and 5 ones
391= 3 hundreds, 9 tens, and 1 one
You can use the model I attached to help u see it better.
Hope this helps!

6 0

3 years ago

Please help me with these two math problems that I do not quite understand. This is urgent!

g100num [7]

Answer:

1) $a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19$

2) $a_{10}=4+8(10-1)\Rightarrow a_{10}=76$

Step-by-step explanation:

1) To write an Arithmetic Sequence, as an Explicit Term, is to write a general formula to find any term for this sequence following this pattern:

$a_{n}=a_{1}+d(n-1)\Rightarrow \left\{\begin{matrix}a_{n}=n^{th}\: term\\a_1=1st \: term \\d=\: difference\\n=n^{th}\, term\end{matrix}\right.$

<em>"Write an explicit formula for each explicit formula A(n)=-1+(n-1)(-2)"</em>

This isn't quite clear. So, assuming you meant

Write an explicit formula for each term of this sequence A(n)=-1+(n-1)(-2)

As this A(n)=-1+(n-1)(-2) is already an Explicit Formula, since it is given the first term $a_{1}=-1$ the common difference $d=-2$ let's find some terms of this Sequence through this Explicit Formula:

$a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19$

2) $(4,12,20,28, ..)$ In this Arithmetic Sequence the common difference is 8, the first term value is 4.