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4 years ago

Question 23 on this pictured math sheet please. Have a great day!

Mathematics

1 answer:

Alex_Xolod [135]4 years ago

3 0

Answer:

+2x+15

Step-by-step explanation:

-3x+5x=+2x

(+2x-7) × (+8)

(+2x)(+15)

I THINK

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Identify an equation in point-slope form for the line perpendicular to

Alchen [17]

Answer:

$y - 9 = \frac{1}{2}(x +3)$

Step-by-step explanation:

Given

Function; $y = -2x + 8$

Required

Find an equation perpendicular to the given function if it passes through (-3,9)

First, we need to determine the slope of: $y = -2x + 8$

The slope intercept of an equation is in form;

$y = mx + b$

Where m represent the slope

Comparing $y = m_1x + b$ to $y = -2x + 8$ ;

We'll have that

$m_1 = -2$

Going from there; we need to calculate the slope of the parallel line

The condition for parallel line is;

$m_1 * m_2 = -1$

Substitute $m_1 = -2$

$(-2) * m_2 = -1$

Divide both sides by -2

$m_2 =\frac{ -1}{-2}$

$m_2 =\frac{1}{2}$

The point slope form of a line is;

$y - y_1 = m_2(x - x_1)$

Where $(x_1,y_1) = (-3,9)$ and $m_2 =\frac{1}{2}$

$y - y_1 = m_2(x - x_1)$ becomes

$y - 9 = \frac{1}{2}(x - (-3))$

Open the inner bracket

$y - 9 = \frac{1}{2}(x +3)$

Hence, the point slope form of the perpendicular line is: 

 $y - 9 = \frac{1}{2}(x +3)$ 

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3 years ago

Find the distance between the pair of parallel lines, y = x-11 & y = x-7

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jenyasd209 [6]

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Express the area of the triangle shown below in terms of b and θ only.

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Given a right triangle with base, b and height, h with the angle opposide side h as θ.

The area of a triangle is given by
$A= \frac{1}{2} bh$

But,
$\tan\theta= \frac{h}{b} \\ \\ \Rightarrow h=b\tan\theta$

Therefore, the area of the triangle in terms of b and θ only is given by
$A= \frac{1}{2} b(b\tan\theta)= \frac{1}{2} b^2\tan\theta$

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