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Zanzabum
2 years ago
15

A gas system has volume, moles and temperature of 9040 mL, 0.447 moles and -35.50 oC, respectively. What is the pressure in atm?

Chemistry
1 answer:
babymother [125]2 years ago
7 0

Answer : The pressure of the gas is, 0.964 atm

Solution : Given,

Volume of gas = 9040 ml = 9.040 L        (1 L = 1000 ml)

Moles of gas = 0.447 moles

Temperature of gas = -35.50^oC=237.5K       (0^oC=273K)

Using ideal gas equation,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = gas constant = 0.0821Latm/moleK

Now put all the given values in this formula, we get the pressure of the gas.

P(9.040L)=(0.447moles)\times (0.0821Latm/moleK)\times (237.5K)

By rearranging the terms, we get

P=0.964atm

Therefore, the pressure of the gas is, 0.964 atm

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3 years ago
How many grams of chlorine gas can be produced when 50.0 grams of aluminum chloride decompose? 2AlCl3→ 2Al + 3Cl2
lianna [129]

Answer:

Explanation:

Approx.

425

⋅

g

Explanation:

2

A

l

(

s

)

+

3

C

l

2

(

g

)

→

2

A

l

C

l

3

(

s

)

You have given a stoichiometrically balanced equation, so bravo.

The equation explicitly tells us that

54

⋅

g

of aluminum metal reacts with

6

×

35.45

⋅

g

C

l

2

gas to give

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⋅

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of

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6 0
2 years ago
PLEASE HELP ME!!! ASAP
shtirl [24]

Answer:

Theoretical yield of the reaction = 34 g

Excess reactant is hydrogen

Limiting reactant is nitrogen

Explanation:

Given there is 100 g of nitrogen and 100 g of hydrogen

Number of moles of nitrogen = 100 ÷ 28 = 3·57

Number of moles of hydrogen = 100 ÷ 2 = 50

Reaction between nitrogen and hydrogen yields ammonia according to the following chemical equation

N2 + 3H2 → 2NH3

From the above chemical equation for every mole of nitrogen that reacts, 3 moles of hydrogen will be required and 2 moles of ammonia will be formed

Now we have 3·57 moles of nitrogen and therefore we require 3 × 3·57 moles of hydrogen

⇒ We require 10·71 moles of hydrogen

But we have 50 moles of hydrogen

∴ Limiting reactant is nitrogen and excess reactant is hydrogen

From the balanced chemical equation the yield will be 2 × 3·57 moles of ammonia

Molecular weight of ammonia = 17 g

∴ Theoretical yield of the reaction = 2 × 3·57 × 17 = 121·38 g

5 0
3 years ago
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