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The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is : - 0.69°C
<h3>Determine the freezing point of the solution </h3>
First step : Calculate the molality of NaCl
molality = ( 2.5 grams / 58.44 g/mol ) / ( 230 * 10⁻³ kg/ml )
= 0.186 mol/kg
Next step : Calculate freezing point depression temperature
T = 2 * 0.186 * kf
where : kf = 1.86°c.kg/mole
Hence; T = 2 * 0.186 * 1.86 = 0.69°C
Freezing point of the solution
Freezing temperature of solvent - freezing point depression temperature
0°C - 0.69°C = - 0.69°C
Hence the Freezing temperature of the solution is - 0.69°C
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Answer:
CaBr2 is a colorless solid and the charge on Calcium is +2
Explanation:
CaBr2 is a colorless solid at room temperature.
Other properties include -
a) It is a crystalline solid
b) Melting point of 765°C.
c) It is deliquescent
d) Soluble in water and absolute alcohol.
The charge of Br is -1. Here two atoms of Br attaches with one atom of calcium. Hence the charge of calcium is +2
There are 8 neutrons. The mass number subtracted by the atomic number gives you neutrons. if your continuing with isotopes, find the average mass of Oxygen 16
depending on where you live. so if you're in North Carolina it . ( temperature )
