Answer:
36s^5
Explanation:
We have;
M2X3 (s)------> 2M^3+(aq) + 3X^2-(aq)
If [M^3+(aq)] = [X^2-(aq)] = s
We then have;
Ksp = (2s)^2 * (3s)^3
Ksp = 4s^2 * 9s^3
Ksp = 36s^5
Note that Ksp is known as the solubility product. It is an equilibrum equation that shows the solubility of a solute in water.
Answer:
Explanation:
If you insist on filling in the first blank you can put a one.
Answer:
The formula of the compound is:
N2H2
Explanation:
Data obtained from the question:
Nitrogen (N) = 93.28%
Hydrogen (H) = 6.72%
Next, we shall determine the empirical formula for the unknown compound. This is illustrated below:
N = 93.28%
H = 6.72%
Divide by their molar mass
N = 93.28 /14 = 6.663
H = 6.72 /1 = 6.7
Divide by the smallest
N = 6.663 / 6.663 = 1
H = 6.72 /6.663 = 1
Therefore, the empirical formula is NH.
Now, we can obtain the formula of the compound as follow:
The formula of a compound is simply a multiple of the empirical formula.
[NH]n = 30.04
[14 + 1]n = 30.04
15n = 30.04
Divide both side by 15
n = 30.04/15
n = 2
Therefore, the formula of the compound is:
[NH]n => [NH]2 => N2H2
I think the correct answer from the choices listed above is option D. The correct mass of nitrogen would be 2.9 g. The mass is calculated by multiplying the density and the volume of the substance. The correct answer should have two significant figures since it is the least precise operation.
Answer:
1160mg
Explanation:
Molarity = number of moles ÷ volume
According to the information in the question, molarity = 1.25 M, volume = 18.0 mL = 18/1000 = 0.018L
M = n/V
n = M × V
n = 1.25 × 0.018
n = 0.0225moles.
Using mole = mass/molar mass, to find the mass of lithium phosphide (Li3P)
Molar mass of Li3P = 6.9(3) + 31 = 51.7g/mol
mole = mass/molar mass
0.0225 = mass/51.7
mass = 1.16grams.
In milligrams (mg), mass of Li3P = 1.16 × 1000 = 1160mg
