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3 years ago

The group of the periodic table determines the ___.

Chemistry

1 answer:

tatuchka [14]3 years ago

5 0

Answer: C. Number of valence electrons

Explanation: A group is a vertical column in the periodic table, which signifies the number of valence shell electrons in an element's atom. Example: all the elements in group 1 have 1 electron in their outer most shell.

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(BRAINLIEST) Coal burning plants produce less air pollution than nuclear power plants

Alecsey [184]

Answer:

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3 years ago

PLEASE HELP!!!

Inga [223]

Answer:

$d=1.5\ g/cm^3$

Explanation:

Given that,

The mass of the rock, m = 15 g

The volume of the rock, V = 10 cm³

We need to find the density of the rock. The density of an object is equal to the mass per unit volume such that,

$d=\dfrac{m}{V}\\\\d=\dfrac{15\ g}{10\ cm^3}\\\\d=1.5\ g/cm^3$

So, the density of the rock is equal to $1.5\ g/cm^3$ .

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3 years ago

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3 years ago

. Which of the following is a balanced chemical equation for the synthesis of NaBr from Na and Br2?

topjm [15]

Answer: The correct option is:

$2Na+Br_2\rightarrow 2NaBr$

Explanation:

In balanced chemical equation , mass of the reactants is always equal to the mass of the products.

$2Na+Br_2\rightarrow 2NaBr$

This is the balanced equation because on both sides number of sodium and bromine atoms are same.

On the reactant side there are two sodium atoms and two bromine atoms

On the product side there are also two sodium atoms and two bromine atoms in NaBr.

Mass of reactants (here 2Na and $Br_2$ )= Mass of products(here 2NaBr)

2(23u) + 2(79.9u) = 2(23u + 79.9u) = 205 u

3 0

3 years ago

Read 2 more answers

The element magnesium has significantly fewer protons and neutrons than gold. If you were to use MgMg in place of AuAu in the Ru

Vadim26 [7]

Answer:The center will be quite smaller in magnesium than in gold thus the alpha particle will scatter to a lesser degree and the experiment may not yield a meaningful result.

Explanation:

Gold has seventy nine protons and magnesium has only twelve protons. Gold atoms are quite much more massive than magnesium atoms. This implies that if magnesium atoms were used in Rutherford's experiment, the number of protons will be too few to give a reasonable result since the atom is quite small. A larger atom, having a larger centre is required in order to have meaningful scattering of alpha particles.

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3 years ago