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Reptile [31]
3 years ago
7

A balanced relationship between the energy that you intake and your bodys energy output is the definition of _____.

Physics
1 answer:
Jet001 [13]3 years ago
5 0
Whole body METABOLISM
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A bicyclist is in a 50-km race. She says she had an average velocity of 35.
zlopas [31]
The correct answer to this is (A. Units Only).

It shows that there is a velocity of 35, but the units are missing.
8 0
3 years ago
The length of the track itself is 500m. The vehicles (each of mass 15kg) are dragged
gogolik [260]

Answer:

W = 100000 J = 100 KJ

Explanation:

Here we will use the most basic and general formula of work, which is as follows:

W = Fd

where,

W = Work Done = ?

F = Force Required = 200 N

d = Length of Track = 500 m

Therefore,

W = (200\ N)(500\ m)\\

<u>W = 100000 J = 100 KJ</u>

5 0
3 years ago
A 9.0-kg bowling ball on a horizontal, frictionless surface experiences a net force of 6.0 n. what will be its acceleration?
Vladimir [108]

This question involves the concepts of Newton's Second Law of Motion.

The acceleration of the bowling ball will be "0.67 m/s²".

<h3>Newton's Second Law of Motion</h3>

According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,

F=ma\\\\a=\frac{F}{m}

where,

  • a = acceleration = ?
  • F = Magnitude of the applied force = 6 N
  • m = Mass of the ball = 9 kg

Therefore,

a=\frac{6\ N}{9\ kg}

a = 0.67 m/s²

Learn more about Newton's Second Law of Motion here:

brainly.com/question/13447525

#SPJ1

7 0
2 years ago
Avogadro‘s number was calculated by determining The number of atoms in
Lady_Fox [76]

Answer:

12 grams of the isotope carbon-12.

Explanation:

hope it helps you and give me a brainliest

7 0
2 years ago
A metallic wire has a diameter of 4.12mm. When the current in the wire is 8.00A, the drift velocity is 5.40×10−5m/s.What is the
podryga [215]

Answer:

6.9\times 10^{28}m^{-3}

Explanation:

We are given that

Diameter of wire=d=4.12 mm

Radius of wire=rr=\frac{d}{2}=\frac{4.12}{2}=2.06mm=2.06\times 10^{-3} m

1mm=10^{-3} m

Current=I=8 A

Drift velocity=v_d=5.4\times 10^{-5} m/s

We have to find the density of free electrons in the metal

We know that

Density of electron=n=\frac{I}{v_deA}

Using the formula

Density of free electrons=\frac{8}{5.4\times 10^{-5}\times 1.6\times 10^{-19}\times 3.14\times (2.06\times 10^{-3})^2}

By using Area of wire=\pi r^2

\pi=3.14\\e=1.6\times 10^{-19} C

Density of free electrons=6.9\times 10^{28}m^{-3}

3 0
3 years ago
Read 2 more answers
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