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lana [24]
3 years ago
8

State what is meant by graviration potential at a point in an orbit 6.5×10^7​

Physics
1 answer:
laila [671]3 years ago
5 0

Explanation:

The gravitational potential at a point in a gravitational field is the work done per unit mass that would have to be done by some externally applied force to bring a massive object to that point from some defined position of zero potential,

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Which of these statements correctly describe the atom? Check all that apply. All matter on Earth is made up of atoms. The subato
Irina18 [472]

True: All matter on earth is made up of atoms.

False: Subatomic particles don't identify an element. I give you an electron. Can you tell me where it came from?

False: (1/2) A neutron has no charge [That's the True part]. It identifies the element. (Not true).

True: description of an electron.

True: description of a proton

3 0
4 years ago
Read 3 more answers
Part 1
nlexa [21]

The force exerted by the hammer claws on the nail is =1578N

<h3 /><h3>How to calculate magnitude of force:</h3>

The force that is applied, as the effort on the hammer= F1

The force exerted by the hammer claws on the nail= F2

But,

magnitude of force exerted on hammer= F1*d1

While magnitude of force exerted by the hammer claws on the nail = F2( d2sin30°)

And, F1*d1 = F2( d2sin30°)

Where F1 = 133N

d1 = 29cm = 0.29m

F2 = X

d2 = 4.89cm = 0.0489m

After substitution,

133 × 0.29 = X( 0.0489 × sin30°)

38.57 = X ( 0.0489 × 0.5)

38.57 = X(0.02445)

X= 38.57/0.02445

X = 1578N

Therefore, the force exerted by the hammer claws on the nail is =1578N

Learn more about force here:

brainly.com/question/25239010

3 0
3 years ago
. A truck is traveling at a speed of 25.0 m/sec along a level road. A crate is resting on the bed of the truck, and the coeffici
OLga [1]

Answer:

98.12 m

Explanation:

Initial speed(v) = 25.0 m/s

Coefficient of static friction (u) = 0.650

The minimum value of the coefficient of kinetic friction should be the coefficient of static friction.

Kinetic friction is given as

umg = ma (a is the required acceleration)

We then have

a = -ug

= -(0.65*9.8)

= -6.37 m/s^2

The shortest distance d is obtained by

d = (V^2 - v^2)/ 2a

V = 0 m/s (final velocity)

d = (0 - 25^2) / 2(-6.37)

d = -625/-6.37

d = 98.12 m

5 0
3 years ago
URGENT HELP PLS
Andre45 [30]

Answer:constant amount of work is done

8 0
3 years ago
5
Brilliant_brown [7]

25+50-30-40 = 0

north and east are positive directions, south and west are negative

hope this helps

also hope u enjoy a pic of my crush lol

3 0
4 years ago
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