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3 years ago

What unita are used to measure electrical current

Physics

2 answers:

BigorU [14]3 years ago

5 0

Answer:

to me Current is like a type of quantified in amps and resistance is also measured measured in something like ohms. The specific unit of measure for current is amperes. To measure current, you must connect the two leads of the ammeter in the circuit so that the current flows through the ammeter.

Explanation:

JulijaS [17]3 years ago

4 0

Answer:

It's called an ampere!

Explanation:

The SI unit of electric current is the ampere, which is the flow of electric charge across a surface at the rate of one coulomb per second. The ampere (symbol: A) is an SI base unit Electric current is measured using a device called an ammeter.

Hope this helps :)

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You and your friend are pushes hard against a stationary wall. If you push 3 times harder than your friend, then the amount of w

shtirl [24]

Answer:

Work = F * s where s is the distance F moves

Since F is stationary, in this case, "no work" is done by either person

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1 year ago

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2 years ago

The intensity of the radiation from the Sun measured on Earth is 1360 W/m2 and frequency is f = 60 MHz. The distance between the

Mama L [17]

Answer: (a) power output = 3.85×10²⁶W

(b). There is no relative change in power as it is independent from frequency

(c). 590 W/m²

Explanation:

given Radius between earth and sun to be = 1.50 × 10¹¹m

Intensity of the radiation from the sun measured on earth to be = 1360 W/m²

Frequency = 60 MHz

(a). surface area A of the sun on earth is = 4πR²

substituting value of R;

A = 4π(.50 × 10¹¹)² = 2.863 10²³×m²

A = 2.863 10²³×m²

now to get the power output of the sun we have;

P sun = I sun-earth A sun-earth

where A = 2.863 10²³×m², and I  is 1360 W/m²

P sun = 2.863 10²³ × 1360

P sun = 3.85×10²⁶W

(c). surface area A of the sun on mars is = 4πR²

now we substitute value of 2.28 ×10¹¹ for R sun-mars, we have

A sun-mars = 4π(2.28× 10¹¹)²

A sun-mars = 6.53 × 10²³m²

now to calculate the intensity of the sun;

I sun-mars = P sun / A sun-mars

where P sun = 3.85×10²⁶W and A sun-mars = 6.53 × 10²³m²

I sun-mars = 3.85×10²⁶W / 6.53 × 10²³m²

I sun-mars = 589.6 ≈ 590 W/m²

I sun-mars = 590 W/m²

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3 years ago

Which statements describe nuclear reactions? Check all that apply.

Alexandra [31]

Explanation:

Nuclear reactions are the reactions in which nucleus of an atom changes either by splitting or joining with the nucleus of another atom.

There are two types of nuclear reactions.

Nuclear fission - In this process, large atomic nuclei splits into smaller nuclei.
Nuclear fusion - In this process, two small nuclei combine together to form a large nuclei.

Both nuclear fission and fusion processes involve nuclei of atoms.

For example, $^{0}n + ^{235}_{92}U \rightarrow ^{236}_{92}U \rightarrow ^{144}_{56}Ba + ^{89}_{36}Kr + 3n + 177 MeV$