Answer:
7 m .
Explanation:
For destructive interference
Path difference = odd multiple of λ /2
Wave length of sound from each of A and B.
= speed / frequency
λ = 334 / 172 = 2 m
λ/2 = 1 m
If I am 1 m away from B , the path difference will be
8 - 1 = 7 m which is odd multiple of 1 or λ /2
So path difference becomes odd multiple of λ /2.
This is the condition of destructive interference.
So one meter is the closest distance which I can remain at so that i can hear destructive interference.
Explanation:
Electrons will gain energy as they are "pushed" from different points in the circuit. This energy is then lost when the electrons flow through circuit components such as a light bulb.
Correct Answer is B.
In a parallel circuit, the voltage is same across all the branches however the current in each branch is different and depends on the resistance of that branch.
Points to Remember:
1) In series circuit current remains the same and voltage varies
2) In parallel circuit voltage remains the same and current varies
Answer:
Explanation:
Given that,
Hot temperature
T_H = 96°F
From Fahrenheit to kelvin
°K = (°F - 32) × 5/9 + 273
°K = (96 - 32) × 5/9 + 273
K = 64 × 5/9 + 273 = 35.56 + 273
K = 308.56 K
T_H = 308.56 K
Low temperature
T_L = 70°F
Same procedure to Levine
T_L = (70-32) × 5/9 + 273
T_L = 294.11 K
A carnot refrigerator working between a hot reservoir and at temperature T_H and a cold reservoir and at temperature T_L has a coefficient of performance K given by
K = T_L / (T_H - T_L)
K = 294.11 / (308.56 - 294.11)
K = 294.11 / 14.45
K = 20.36
Then, the coefficient of performance is the energy Q_L drawn from the cold reservoir as heat divided by work done,
So, for each joules W = 1J
K = Q_L / W
Then,
Q_L = K•W
Q_L = 20.36 × 1
Q_L = 20.36 J
Q_L ≈ 20J
So, approximately 20J of heats are removed from the room
