Answer: 28.40
Explanation:
For A(27.977 u)
Mass number = 27.977
Abundance = 78.21%
For B (28.976 u)
Mass number = 28.976
Abundance = 1.346%
For C(29.974 u)
Mass number = 29.974
Abundance = 20.444%
Averages atomic mass
= (Mass of A x abundance of A)/100 + (Mass of B x abundance of B)/100 + (Mass of C x abundance of C)/100
= (27.977x78.21)/100 + (28.976x1.346)/100 + (29.974x20.444)/100
= 21.8808117 + 0.39001696 + 6.12788456
= 28.40
Answer:contact forces or transfer energy(not sure)
Explanation:
Answer : The ratio of hydrogen and oxygen in water is, (2:1)
Explanation :
As we know that the chemical formula of water is, .
In , there are 2 atoms of hydrogen and 1 atom of oxygen.
As we are given that the volume of water is, 2 L. So, there is no matter what is the volume of water that means there is no role of volume of water.
The ratio of hydrogen and oxygen in water is, (2:1)
Thus, in 2 L volume of water, the ratio of hydrogen and oxygen in water is also same that is, (2:1)
Answer:
0.12693 mg/L
Explanation:
First we <u>calculate the concentration of compound X in the standard prior to dilution</u>:
- 10.751 mg / 100 mL = 0.10751 mg/mL
Then we <u>calculate the concentration of compound X in the standard after dilution</u>:
- 0.10751 mg/mL * 5 mL / 25 mL = 0.021502 mg/L
Now we calculate the<u> concentration of compound X in the sample</u>, using the <em>known concentration of standard and the given areas</em>:
- 2582 * 0.021502 mg/L ÷ 4374 = 0.012693 mg/L
Finally we <u>calculate the concentration of X in the sample prior to dilution</u>:
- 0.012693 mg/L * 50 mL / 5 mL = 0.12693 mg/L