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3 years ago

What will replace aluminum in a single replacement reaction

Chemistry

2 answers:

Liula [17]3 years ago

7 0

C. K since it is above Aluminium in the reactivity series

Leviafan [203]3 years ago

5 0

C. K

Recall the activity series of metals. The order is

K > Al > Mn > Zn

Mn and Zn are below Al in the activity series.

<em>K</em> is the only metal that is <em>above Al</em>.

∴ K will replace Al in a single displacement reaction.

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What is hydrocabron

navik [9.2K]

Answer:

Hydrocarbon is a Compound that is made up of Carbon and Hydrogen .

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3 years ago

10) The presence of nitrates in soil can be shown by warming the soil with

tresset_1 [31]

Answer:

ammonia

Explanation:

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2 years ago

Which statement about surface tension is FALSE?

Georgia [21]

Answer: B (Items with densities lower than water will sink due to surface tension)

Explanation:

Surface tension is an intermolecular force exerted on the surface of water making it like a stretch elastic skin. Surface tension enables items with lesser densities than water, to float and slide on a water surface. Examples insects, leaves, paper etc

According to Archimedes principle an object denser than the fluid will sink. While objects less dense than the fluid will float.

Answer is (B) is false because items with densities higher then water will sink due to surface tension

5 0

3 years ago

A reaction of 41.9 g of Na and 30.3 g of Br2 yields 36.4 g of NaBr . What is the percent yield?

Licemer1 [7]

Answer: The percent yield is, 93.4%

Explanation:

First we have to calculate the moles of Na.

$\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles$

Now we have to calculate the moles of $Br_2$

${\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles$

${\text{Moles of } NaBr} = \frac{\text{Mass of } NaBr }{\text{Molar mass of } NaBr} =\frac{36.4g}{103g/mole}=0.353moles$

The balanced chemical reaction is,

$2Na(s)+Br_2(g)\rightarrow 2NaBr$

As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = $\frac{2}{1}\times 0.189=0.378$ moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

As, 1 mole of bromine give = 2 moles of Sodium bromide

So, 0.189 moles of bromine give = $\frac{2}{1}\times 0.189=0.378$ moles of Sodium bromide

Now we have to calculate the percent yield of reaction

$\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100=\frac{0.353 mol}{0.378}\times 100=93.4\%$

Therefore, the percent yield is, 93.4%

3 0

3 years ago

Which family in the periodic table has elements that are silvery and lustrous?

IrinaVladis [17]

The correct answer is A. Alkali metals.
I hope this helped

6 0

3 years ago

Read 2 more answers