Answer:
84.24 g
Explanation:
Given data:
Mass of oxygen = 75 g
Mass of Al required to react = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 75 g/ 32 g/mol
Number of moles = 2.34 mol
Now we will compare the moles of oxygen with Al.
O₂ : Al
3 : 4
2.34 : 4/3×2.34 = 3.12 mol
Mass of Al required:
Mass = number of moles × molar mass
Mass = 3.12 mol × 27 g/mol
Mass = 84.24 g
Answer:
There are 14 cm in 0.14 m
Answer:
350.64g
Explanation:
So first you must know that M is mol/L
Next solve the problem using dimensional analysis
2L NaCl (3 mol/L) = 6 mol NaCl
After you got the number of moles you should look at your periodic table to find the molar mass
I see that it's 58.44g/mol
Use dimensional analysis again!
6 mol (58.44g/mol) = 350.64g
Don't forget to make me brainliest!
Answer:- oxygen.
Explanations:- The electronic configuration is given and we are asked to figure out the electrically neutral atom that will have the electron configuration, .
The sum of electrons for this electron configuration is 8. If we look at the periodic table then 8 is the atomic number of oxygen.
So, the electrically neutral atom for the given electron configuration is oxygen.