All categories

2 years ago

How a diode can act as a capacitor?

1 answer:

maks197457 [2]2 years ago

3 0

A diod can act as a capacitor the deplition region in diod acts as a capacitor as it also stores energy similar to capacitor in electric field.

You might be interested in

What is the period of a wave traveling 5 m/s if its wavelength is 20 m/s

Ilia_Sergeevich [38]

Speed of wave is given as

$v = 5 m/s$

Wavelength of the wave is given as

$\lambda = 20 m$

now from the formula of wave time period we can say

$speed = \frac{wavelength}{time period}$

$5 = \frac{20}{T}$

$T = \frac{20}{5}$

$T = 4 s$

so it will have time period of T = 4 s

7 0

3 years ago

What is the following atmospheric property associated with?

Nadya [2.5K]

Answer:

Your answer should be Cooled Air

Explanation:

6 0

2 years ago

An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W inc

Yanka [14]

Answer:

LED bulb = 0.145 A

Incandescent bulb = 0.909 A

CFL bulb = 0.218 A

Explanation:

Given:

Power rating of LED bulb (P₁) = 16 W

Power rating of incandescent bulb (P₂) = 100 W

Power rating of CFL bulb (P₃) = 24 W

Terminal voltage across the circuit (V) = 110 V

We know that, power is related to terminal voltage and current drawn as:

$P=VI$

Express this in terms of 'I'. This gives,

$I=\frac{P}{V}$

Now, calculate the current drawn in each bulb using their respective values.

For LED bulb, $P_1=16\ W, V=110\ V$

So, current drawn is given as:

$I_1=\frac{16\ W}{110\ V}=0.145\ A$

For incandescent bulb, $P_2=100\ W, V=110\ V$

So, current drawn is given as:

$I_2=\frac{100\ W}{110\ V}=0.909\ A$

For CFL bulb, $P_3=24\ W, V=110\ V$

So, current drawn is given as:

$I_3=\frac{24\ W}{110\ V}=0.218\ A$

Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

5 0

3 years ago

Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing fo

defon

Answer:

$F = 26.04 N$

Explanation:

As we know that system of two boxes are moving on frictionless surface

So here if two boxes are considered as a system

then we have

$F = (m_1 + m_2) a$

$m_1 = 24 kg$

$m_2 = 62 kg$

$F = 36 N$

$36 = (24 + 62) a$

$a = 0.42 m/s^2$

Now since we know that both the boxes are moving together so force applied by first box on other box is given as

$F = ma$

$F = (62 \times 0.42)$

$F = 26.04 N$

6 0

3 years ago

S.I. Units Ampere is use for what?

lawyer [7]

The ampere (symbol: A) is the SI base unit of electric current equal to one coulomb per second.

The ampere is that constant current which, if maintained in two straight parallel conductors of infinite length, of negligible circular cross section, and placed 1 meter apart in vacuum, would produce between these conductors a force equal to 2 times 10–7 newton per meter of length.

Electric current is the time rate of change or displacement of electric charge.

One ampere represents the rate of 1 coulomb of charge per second.

The ampere is defined first (it is a base unit, along with the meter, the second, and the kilogram), without reference to the quantity of charge.

The unit of charge, the coulomb, is defined to be the amount of charge displaced by a one ampere current in the time of one second.

This is your answer friend. Hope it helps you.

3 0

2 years ago