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makkiz [27]
3 years ago
5

A stone was dropped off a cliff and hit the ground with a speed of 96 ft/s. What is the height of the cliff? (Use 32 ft/s2 for t

he acceleration due to gravity.)
Physics
1 answer:
nadezda [96]3 years ago
4 0
The initial velocity of the stone is 0 ft/s. Given the initial velocity (Vi), final velocity (Vf), and acceleration due to gravity (g), the distance may be calculated through the equation,
                                     d = ((Vf)² - (Vi)²) / 2g
Substituting the known values,
                                     d = ((96 ft/s)² - 0))/ (2x32.2)
The value of d is 143.10 ft. 
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The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The
True [87]

Answer:

Explanation:

Capacitance of capacitor

= ε₀ A / d , ε₀ is permittivity of space , A is area of plate , d is distance between plates.

= 8.85 x 10⁻¹² x 2 x 10⁻³ / (6 x 10⁻³)

= 2.95 x 10⁻¹² F

Electric field E = V / d , V is potential difference

V = E x d

= 100 x 10³ x 6 x 10⁻³

= 600 V

Charge on the capacitor

= capacitance x potential difference

= 2.95 x 10⁻¹² x 600

= 17.7 x 10¹⁰ C

3 0
3 years ago
The four wheels of a car are connected to the car's body by spring assemblies that let the wheels move up and down over bumps an
Marrrta [24]

Answer:k=55.590 KN/m

Explanation:

Given

mass of person\left ( m\right )=68 kg

car dips about 1.2 cm

We know

F=kx

Where k=combined  spring constant

mg=kx

k=\frac{mg}{x}

k=\frac{68\times 9.81}{1.2\time 10^{-2}}

k=55.590 KN/m

7 0
3 years ago
Identifying the factors contributing to and acting as determinant factors of health disparities during the program theory and de
Sav [38]

Answer:

a) True

Explanation:

A program-specific message provided to an individual or group with the intention of raising awareness of a health condition, motivating behavior change, removing perceived barriers to participating in a health habit, or something else relating to the program's aims and objectives. The most effective intervention messages are usually theory-based and culturally adapted.

5 0
2 years ago
An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves r
alexandr402 [8]
Hi there, 
for this question we have:
Signal 2.0 MHz = Emitted so we can call it f_e
and we need the Reflected = f_{r}
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted). 
we also know: ΔBeat frequency(max) = 560 Hz = f_{b}
so we have: 
f_{e} - f_{r} = f_{b}
so frequency of Reflected is: 
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz = f_{r}
now you know that Lambda = v/f 
so if we find the lambda with our Emitted then we can find v with the Reflected: 
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m 
=> v_{max} = (lambda)(f_{r} 
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s 
so the v_{max} is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day

8 0
3 years ago
4. A rock is thrown from the edge of the top of a 100 m tall building at some unknown angle above the horizontal. The rock strik
nikklg [1K]

Answer:

Explanation:

Let the velocity of projectile be v and angle of throw be θ.

The projectile takes 5 s to touch the ground during which period it falls vertically by 100 m

considering its vertical displacement

h = - ut +1/2 g t²

100 = - vsinθ x 5 + .5 x 9.8 x 5²

5vsinθ =  222.5

vsinθ = 44.5

It covers 160 horizontally in 5 s

vcosθ x 5 = 160

v cosθ = 32

squaring and adding

v²sin²θ +v² cos²θ = 44.4² + 32²

v² = 1971.36 + 1024

v = 54.73 m /s

5 0
3 years ago
Read 2 more answers
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