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Lunna [17]
2 years ago
10

What is the momentum of a bird with a mass of 0.018kg flying at 15m/s?

Physics
1 answer:
Mazyrski [523]2 years ago
6 0

Answer:

0.27 kg-m/s

Explanation:

i believe this is the correct answer

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Amy uses 20N of force to push a lawn mower 10 meters. How much work does she do? *
babunello [35]

She does 200J .

We know she uses 20N of force and 10m is the distance. We multiply both numbers and we are given our answer of 200J. Hope this was helpful. :)

4 0
3 years ago
Light hits a mirror at a 45° angle. It will be reflected at an angle _____.
Eddi Din [679]
It will be equal to 45°
6 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH MY PHYSICS QUESTIONS? I NEED CORRECT ANSWERS ONLY!
BARSIC [14]
<h2>Right answer: acceleration due to gravity is always the same </h2><h2 />

According to the experiments done and currently verified, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is <u>the acceleration of gravity</u>.  

Now, in this case we are on Earth, so the gravity value is 9.8\frac{m}{s^{2}}  

Note the objects experience the acceleration of gravity regardless of their mass.

Nevertheless, on Earth we have air, hence <u>air resistance</u>, so the afirmation <em>"Free fall is a situation in which the only force acting upon an object is gravity" </em>is not completely  true on Earth, unless the following condition is fulfiled:

If the air resistance is <u>too small</u> that we can approximate it to <u>zero</u> in the calculations, then in free fall the objects will accelerate downwards at 9.8\frac{m}{s^{2}} and hit the ground at approximately the same time.  


5 0
3 years ago
A 4,000 kg boat floats with one-third of its volume submerged. if two more people get into the boat, each of whom weighs 690 n,
AveGali [126]

 

The weightiness of the added water displaced is equivalent to the joined weight of the two extra people who come to be into the boat:


<span>m water g                   = 2 x 690 N</span>

<span>                                   = 1,380 N</span>

<span>
</span>

The mass of the water displace is then


<span>m water g                   = 1,380 N</span>

<span>                                   = 1,380 N / 9.8 m/s^2</span>

<span>                                   = 141 kg</span>

<span>
</span>

Compute the calculation for density for the volume of water displace and practice this outcome for the mass of the water displace to get the answer:


<span>p water                      = mass of water / volume of water</span>

<span>
</span>

<span>volume of water        = mass of water / p water</span>

<span>                                  = 141 kg / 1000 kg /m^3 eliminate kilogram</span>

<span>                                  = 0.14 m^3 the additional volume of water that is displaced</span>

4 0
3 years ago
How much kinetic energy does a system containing 3 moles of an ideal gas at 300 K possess? What is the heat capacity at constant
ElenaW [278]

Answer:

1. K.E = 11.2239 kJ ≈ 11.224 kJ

2. C_{V} = 37.413 JK^{- 1}

3. Q = 10.7749 kJ

Solution:

Now, the kinetic energy of an ideal gas per mole is given by:

K.E = \frac{3}{2}mRT

where

m = no. of moles = 3

R = Rydberg's constant = 8.314 J/mol.K

Temperature, T = 300 K

Therefore,

K.E = \frac{3}{2}\times 3\times 8.314\times 300

K.E = 11223.9 J = 11.2239 kJ ≈ 11.224 kJ

Now,

The heat capacity at constant volume is:

C_{V} = \frac{3}{2}mR

C_{V} = \frac{3}{2}\times 3\times 8.314 = 37.413 JK^{- 1}

Now,

Required heat transfer to raise the temperature by 15^{\circ} is:

Q = C_{V}\Delta T

\Delta T = 15^{\circ} = 273 + 15 = 288 K

Q = 37.413\times 288 = 10774.9 J = 10.7749 kJ

8 0
3 years ago
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