-2x + 6y = -34
-x + 3y = -17
x = 3y +17
Sub this into 1st eqn
5(3y + 17) + 2y = 21
15y + 85 + 2y =21
17y = -64
y = -3.7647 (to 5 sig. fig.)
y = -3.8 (to nearest tenth)
Sub y = -3.7647 into 2nd eqn
x = 3(-3.7647) +17
x = 5.7 (to nearest tenth)
Answer:
sqrt(67)
Step-by-step explanation:
sqrt(23×3-2)
sqrt(69-2)
sqrt(67)
The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
Answer: a. 90°
Step-by-step explanation:
We know that the in a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.
In the problem∠XYZ is the inscribed angle
∠XYZ=
⇒ ∠XYZ=
Since XZ is a diameter of the circle which is a line segment, thus ∠XZ=180°
∴ ∠XYZ=
∴ ∠XYZ=
Therefore, a. 90° is the measure of ∠XYZ.
X= 4+ 3/7
x= 31/7
hope it could help u