Question

A pyramid has a square base with edges that measure 6 meters, and a slant height of 7.5 meters. What is its surface area?

Answer 1

The area of base:

$B=6^2=36\ m^2$

The area of one side:

$S=\dfrac{1}{2}\cdot6\cdot7.5=22.5\ m^2$

The surface area:

$SA=B+4S\to SA=36+4\cdot22.5=126\ m^2$

Answer 2

Answer: 126 square meters.

Step-by-step explanation:

Given : A pyramid has a square base with edges that measure 6 meters, and a slant height of 7.5 meters.

The surface area of a pyramid ith square base is given by :_

$SA=b^2+2\times(bs)$ , where b = base length and s is the slant height.

For the given situation , we have

b= 6 m

s= 7.5 m

Then , the surface area for the pyramid will be :-

$SA=(6)^2+2\times(6\times7.5)\\\\=36+90=126\ m^2$

Hence, the surface area of the given pyramid = 126 square meters.