Answer:
Well, 60 (minutes in an hour) divided by 12 (from the problem) is 5, so you have to multiply that 5 by the 5 from the problem to find that the train is going 25 (5*5) mph. Just double this for two hours, and you result in 50!
Step-by-step explanation:
13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0
Recall the double angle identity,
sin^2(x) = (1 - cos(2x))/2
If we let x = 13pi/12, then
sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]
where we took the negative square root because we expect a negative value.
Now, because cosine has a period of 2pi, we have
cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2
Then
sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]
sin(13pi/12) = - sqrt[2 - sqrt[3]]/2
Answer:
16x + 8y -3/2
Step-by-step explanation:
The expression can be represented mathematically as follows.
-2(-8x - 4y + 3/4) = - 10x - 8y - 1 1/4
-2(-8x - 4y + 3/4) = - 10x - 8y - 5/4
The first way to solve this expression is by opening the bracket by multiplying the outside values by the inner values.
-2(-8x - 4y + 3/4)
Multiply -2 by all the values in the brackets
-2 × - 8x = 16x not - 10x
-2 × - 4y = 8y not -8y
-2 × 3/4 = -6/4 = - 3/2 not -5/4
Bringing the value together the expected answer will be 16x + 8y -3/2 and not - 10x - 8y - 5/4.
Answer: 119
Step-by-step explanation:
Since the prior estimate of population proportion of defective handles (p) is unknown , so we take p= 0.5
Given : Margin of error : E=0.09
Critical value for 95% confidence interval : ![z_{\alpha/2}=1.96](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3D1.96)
Required sample size :-
![n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.09})^2\\\\=118.567901235\approx119](https://tex.z-dn.net/?f=n%3D0.5%281-0.5%29%28%5Cdfrac%7Bz_%7B%5Calpha%2F2%7D%7D%7BE%7D%29%5E2%5C%5C%5C%5C%3D0.25%28%5Cdfrac%7B1.96%7D%7B0.09%7D%29%5E2%5C%5C%5C%5C%3D118.567901235%5Capprox119)
Hence, the minimum sample size required = 119
i.e. 119 handles from the shipment should be inspected.