<u>Given:</u>
Charge on potassium (K) = +1
Charge on selenium (Se) = -2
<u>To determine:</u>
The values of X and Y in K(X)Se(Y)
<u>Explanation:</u>
The molecule which is formed between K and Se is neutral.
The K+ and Se2- ions should combine such that the net charge on the molecule is zero.
X(K+) + Y(Se2-) = 0
X(+1) + Y(-2) = 0
The simplest solution to the above equation is obtained when X = 2 and Y = 1
Thus, the molecule would be: K₂Se₁
Ans: X = 2 and Y = 1; K₂Se₁
The density of the liquid is 0.2 g/mL.
The mass of the liquid is 6 g.
The volume of the liquid is 30.0 mL.
Density = mass/volume = 6 g/30.0 mL = 0.2 g/mL
Answer:
24.5 g of NaCl
Explanation:
We begin from the balanced reaction:
3MgCl₂ + 2Na₃PO₄ → 6NaCl + Mg₃(PO₄)₂
If the sodium phosphate is in excess, then the limting reagent is the magnessium chloride.
We convert mass to moles:
20 g . 1mol / 95.2g = 0.210 moles.
3 moles of MgCl₂ can produce 6 moles of NaCl
0.210 moles of salt, may produce (0.210 . 6) /3 = 0.420 moles
Ratio of reactant is twice the product
We convert the moles to mass:
0.420 mol . 58.45 g/mol = 24.5 g
A. 8,330 --> 8.33 × 10^3
B. 83.3 --> 8.33 × 10^1
C. 0.00833 --> 8.33 × 10^-3
D. 0.0833 --> 8.33 × 10^-2
E. 83,330 --> 8.33 × 10^4
Hope this helps!