All categories

3 years ago

What is the study of acid-base chemistry called in the environment

Chemistry

1 answer:

Charra [1.4K]3 years ago

8 0

Answer:

An acid is a substance that donates protons (in the Brønsted-Lowry definition) or accepts a pair of valence electrons to form a bond (in the Lewis definition). A base is a substance that can accept protons or donate a pair of valence electrons to form a bond. Bases can be thought of as the chemical opposite of acids.

You might be interested in

A certain metal M forms a soluble sulfate salt MSO, Suppose the left half cell of a galvanic cell apparatus is filled with a 3.0

bija089 [108]

Answer:

E = 0.062 V

Explanation:

(a) See the attached file for the answer

(b)

Calculating the voltage (E) using the formula;

E = - (2.303RT/nf)log Cathode/Anode

Where,

R = 8.314 J/K/mol

T = 35°C = 308 K

F- Faraday's constant = 96500 C/mol,

n = number of moles of electron = 2

Substituting, we have

E = -(2.303 * 8.314 *308/2*96500) *log (0.03/3)

= -0.031 * -2

= 0.062V

Therefore, the voltmeter will show a voltage of 0.062 V

5 0

2 years ago

Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of

bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

$O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol$ ..[1]

$O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol$ ..[2]

$NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol$ ..[3]

$NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?$ ..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

$2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}$

$2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol$

$2\times \Delta H^o_{4}=470.3 kJ/mol$

$\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol$

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0

3 years ago

1. Energy appears in two forms. What are they?

noname [10]

Number 1 is C number 2 is B and number 3 is also B

5 0

3 years ago

How does the freezing point of water from the ocean compare to distilled water one buys at the store?

Lelechka [254]

Due to prescence of any impurity, there will be change in physical properties of any liquid.

8 0

3 years ago

Read 2 more answers

Hydrogen gas and oxygen gas react to produce water. Both of these gases are present in

bonufazy [111]

Water isn't being produced all around us because the hydrogen and oxygen are present in stable form.

<h3>How come water isn't being produced all around us?</h3>

Water molecule is produced when the unstable hydrogen reacts with unstable oxygen because they are very reactive. Due to their reactive nature, hydrogen and oxygen react with each other forming water molecule. So that's why we can say that water is not being produced around us due to stable form of hydrogen and oxygen.

So we can conclude that Water isn't being produced all around us because the hydrogen and oxygen are present in stable form.

Learn more about water here: brainly.com/question/1313076

#SPJ1

6 0

1 year ago