The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.
<em>"Your question is not complete, it seems to be missing the diagram of the emission spectrum"</em>
the diagram of the emission spectrum has been added.
<em>From the given</em><em> chart;</em>
The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m
The frequency of this emission is calculated as follows;
c = fλ
where;
- <em>c is the speed of light = 3 x 10⁸ m/s</em>
- <em>f is the frequency of the wave</em>
- <em>λ is the wavelength</em>
The energy of the emitted photon corresponding to the orange line is calculated as follows;
E = hf
where;
- <em>h is Planck's constant = 6.626 x 10⁻³⁴ Js</em>
<em />
E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)
E = 3.26 x 10⁻¹⁹ J.
Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.
Learn more here:brainly.com/question/15962928
Covalent and hydrogen bonds
Answer: The order with respect to 
is 1.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![Rate=k[NH_4^+]^x[NO_2^-]^y](https://tex.z-dn.net/?f=Rate%3Dk%5BNH_4%5E%2B%5D%5Ex%5BNO_2%5E-%5D%5Ey)
k= rate constant
x = order with respect to
y = order with respect to A
n = x+y = Total order
From trial 1: ![3.2\times 10^{-3}=k[0.0100]^x[0.200]^y](https://tex.z-dn.net/?f=3.2%5Ctimes%2010%5E%7B-3%7D%3Dk%5B0.0100%5D%5Ex%5B0.200%5D%5Ey)
(1)
From trial 2: ![6.4\times 10^{-3}=k[0.0200]^x[0.200]^y](https://tex.z-dn.net/?f=6.4%5Ctimes%2010%5E%7B-3%7D%3Dk%5B0.0200%5D%5Ex%5B0.200%5D%5Ey)
(2)
Dividing 2 by 1 :![\frac{6.4\times 10^{-3}}{3.2\times 10^{-3}}=\frac{k[0.0100]^x[0.2000]^y}{k[0.0200]^x[0.200]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B6.4%5Ctimes%2010%5E%7B-3%7D%7D%7B3.2%5Ctimes%2010%5E%7B-3%7D%7D%3D%5Cfrac%7Bk%5B0.0100%5D%5Ex%5B0.2000%5D%5Ey%7D%7Bk%5B0.0200%5D%5Ex%5B0.200%5D%5Ey%7D)
therefore x= 1
Thus order with respect to is 1.
Answer:
4 moles of neon
Explanation:
Given data:
Number of moles of neon = ?
Number of atoms of neon = 2.4×10²⁴ atoms
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For given neon atoms:
1 mol = 6.022 × 10²³ atoms
2.4×10²⁴ atoms × 1 mol / 6.022 × 10²³ atoms
0.4×10¹ mol = 4 mol
When a neutral hydrogen atom loses an electron, a positively-charged particle should remain.
