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Solnce55 [7]
3 years ago
14

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass 2kg. When a certain con

stant force acts upon an object with mass , the acceleration of the object is 26m/s^2 . If the same force acts upon another object whose mass is 13 , what is this object's acceleration
Physics
1 answer:
BARSIC [14]3 years ago
3 0

Answer:

The acceleration of the second object is 4 m/s².

Explanation:

Given that,

when the a constant force acts upon an object, the acceleration varies inversely with its mass .

mass\propto \frac{1}{acceleration}

We can rewrite the equation as

\frac{m_1}{m_2}=\frac{a_2}{a_1}

When an a certain constant force acts upon an object with mass 2 kg , the acceleration of the object is 26 m/s².

Here, m_1 = 2 kg, a_1 = 26 m/s²,m_2 = 13 kg and a_2=?

\frac{m_1}{m_2}=\frac{a_2}{a_1}

\frac{2}{13}=\frac{a_2}{26}

\Rightarrow \frac{a_2}{26}= \frac{2}{13}

\Rightarrow {a_2}= \frac{2}{13}\times 26

\Rightarrow a_2=4 m/s²

The acceleration of the second object is 4 m/s².

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H = \frac{u^2 sin^2\theta}{2g} \\\\H = \frac{600^2 (sin \ 30)^2}{2\times 9.8} \\\\H = \frac{600^2 (0.5)^2}{19.6} \\\\H = 4,591.84 \ m

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v^2 = u^2 + 2gh\\\\v^2 = 600^2 + (2 \times 9.8)(4,591.84)\\\\v^2 = 360,000 + 90,000.064\\\\v = \sqrt{450,000.064} \\\\v = 670.82 \ m/s

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