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bulgar [2K]
2 years ago
10

The critical path is the sequence of activities that determine the latest date by which the project can be evaluated.

Physics
1 answer:
Leviafan [203]2 years ago
3 0

The statement given about the critical path is true.

To find the answer, we have to know more about the critical path.

<h3>What is critical path?</h3>
  • The longest series of tasks in a project plan that must be finished on time for it to be finished by the deadline is known as the critical path.
  • The critical route is the set of actions that, when carried out in a timely manner while taking into account all the aforementioned factors, will take the longest to accomplish the project.
  • Because it is the "red alert" of paths, the critical path is referred to as "critical".
  • Your project won't be successfully completed before the deadline if it doesn't follow the critical path's timing and order.

Thus, we can conclude that, the statement given about the critical path is true.

Learn more about the critical path here:

brainly.com/question/15091786

#SPJ4

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Brums [2.3K]

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3 years ago
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A ‘thermal tap’ used in a certain apparatus consists of a silica rod which
abruzzese [7]

Correct question is;

A thermal tap used in a certain apparatus consists of a silica rod which fits tightly inside an aluminium tube whose internal diameter is 8mm at 0°C.When the temperature is raised ,the fits is no longer exact. Calculate what change in temperature is necessary to produce a channel whose cross-sectional is equal to that of the tube of 1mm. (linear expansivity of silica = 8 × 10^(-6) /K and linear expansivity of aluminium = 26 × 10^(-6) /K).

Answer:

ΔT = 268.67K

Explanation:

We are given;

d1 = 8mm

d2 = 1mm

At standard temperature and pressure conditions, the temperature is 273K.

Thus; Initial temperature; T1 = 273K,

Using the combined gas law, we have;

P1×V1/T1 = P2×V2/T2

The pressure is constant and so P1 = P2. They will cancel out in the combined gas law to give:

V1/T1 = V2/T2

Now, volume of the tube is given by the formula;V = Area × height = Ah

Thus;

V1 = (πd1²/4)h

V2 = (π(d2)²/4)h

Thus;

(πd1²/4)h/T1 = (π(d2)²/4)h/T2

π, h and 4 will cancel out to give;

d1²/T1 = (d2)²/T2

T2 = ((d2)² × T1)/d1²

T2 = (1² × T1)/8²

T2 = 273/64

T2 = 4.23K

Therefore, Change in temperature is; ΔT = T2 - T1

ΔT = 273 - 4.23

ΔT = 268.67K

Thus, the temperature decreased to 268.67K

6 0
3 years ago
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ZanzabumX [31]
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Answer:

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y = size of the object

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B. +m

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