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3 years ago

How are particle movement and heat related?

Chemistry

1 answer:

sergejj [24]3 years ago

5 0

Because the heat starts a reaction. The answer is called activation energy

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1. Which statements represent properties of intermolecular forces? Select all that apply.

kumpel [21]

Answer:

Explanation:

Only this choice is applicable and correct.

The inter-molecular forces of attraction between the molecules must have been broken (overcome) before the molecules can gain an increase in the kinetic energies between them.

8 0

3 years ago

Draw a structural formula for trans-1-bromo-3-isopropylcyclobutane.

LUCKY_DIMON [66]

We have to draw the structural formula of trans-1-bromo-3-isopropylcyclobutane.

The structure is shown below in Figure1.

The molecule trans-1-bromo-3-isopropylcyclobutane has four atoms in the skeleton and Br atom is attached at 1 position and isopropyl group at 3-position.

Trans structure means both groups are in opposite directions.

5 0

3 years ago

In a solution there is usually more ____________than ___________ A) solute/solvent B) soluble/insoluble C) saturation/unsaturati

Elan Coil [88]

Answer:

I think the answer is option 3

5 0

3 years ago

What is the definition of DNA in meiosis

Eddi Din [679]

In meiosis, DNA replication is followed by two rounds of cell division to produce four daughter cells, each with half the number of chromosomes as the original parent cell. The two meiotic divisions are known as meiosis I and meiosis II.

Explanation:

5 0

3 years ago

The equilibrium constant for the reaction 2NO(g)+Br2(g)⥫⥬==2NOBr(g) is Kc=1.3×10−2 at 1000 K. At this temperature does the equil

o-na [289]

Answer :

The equilibrium favors NO and $Br_2$ .

(1) The value of equilibrium constant for this reaction is, 76.9

(2) The value of equilibrium constant for this reaction is, 8.77

Explanation:

The given chemical equation is:

$2NO(g)+Br_2(g)\rightarrow 2NOBr(g)$

The value of equilibrium constant for the above equation is $K_c=1.3\times 10^{-2}$ .

The value of $K_c$ that means equilibrium lies to the left side. Thus, the equilibrium favors NO and $Br_2$ .

We need to calculate the equilibrium constant for the given equation of above chemical equation, which is:

(1) $2NOBr(g)\rightarrow 2NO(g)+Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_1}=\frac{1}{K_c}$

$K_{c_1}=\frac{1}{1.3\times 10^{-2}}=76.9$

Thus, the value of equilibrium constant for this reaction is, 76.9

(2) $NOBr(g)\rightarrow NO(g)+\frac{1}{2}Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '1/2', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_2}=(\frac{1}{K_c})^{1/2}$

$K_{c_2}=(\frac{1}{1.3\times 10^{-2}})^{1/2}=8.77$

Thus, the value of equilibrium constant for this reaction is, 8.77

7 0

3 years ago

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