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MaRussiya [10]
3 years ago
11

A chemist dissolves 239 mg of pure potassium hydroxide in enough water to make up of solution. Calculate the pH of the solution.

(The temperature of the solution is .) Round your answer to significant decimal places.

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
7 0

Answer: the pH is 11.78

Explanation:Please see attachment for explanation

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N the reaction Mg + 2HCl -> MgCl2 + H2 which element’s oxidation number does not change?
BartSMP [9]

Answer:- Oxidation number of Cl does not change as it is -1 on both sides.

Explanations:- oxidation number of Mg on reactant side is 0 as it is in its elemental form(not combined with another element).

Oxidation number  of hydrogen in its compounds is +1, so if H is +1 in HCl the oxidation number of Cl is -1 as the sum has to be zero.

On product side, Mg oxidation number is +2 as the oxidation number of alkaline earth metals in their compounds is +2.

Two Cl are present in magnesium chloride, so if Mg is +2 then Cl is -1.

Oxidation number of H on product side is 0 as it is present in its elemental for, H_2 ,

So, it is only chlorine(Cl) whose oxidation number does not change for the given equation.


4 0
3 years ago
The visible spectrum of the Cr(acac)3
Sati [7]

Explanation:

The observable visible spectrum of Cr(acac)3 complex is different from that of

[Cr(en)3]Br3 due to strength of bonded ligand in the coordination sphere.

en is a strong field ligand compared to acac thus pairing  occurs. In both the complexes

Cr is in +3 state, configuration [Ar] 3d^3. There are 3 unpaired e in Cr(acac)3 whereas 1 unpaired e in [Cr(en)3]Br3 due to pairing.

3 0
3 years ago
A solution was prepared by dissolving 2.2 g of an unknown solute in 16.7 g of CCl4. A thermal analysis was performed for this so
laila [671]

Answer:

Molar mass of unknown solute is 679 g/mol

Explanation:

Let us assume that the solute is a non-electrolyte.

For a solution with non-electrolyte solute remains dissolved in it -

Depression in freezing point of solution, \Delta T_{f}=K_{f}.m

where, m is molality of solute in solution and K_{f} is cryogenoscopic constant of solvent.

Here \Delta T_{f}=(-22.9^{0}\textrm{C})-(-28.7^{0}\textrm{C})=5.8^{0}\textrm{C}

If molar mass of unknown solute is M g/mol then-

                 m=\frac{\frac{2.2}{M}}{0.0167}mol/kg

So, 5.8^{0}\textrm{C}=29.9^{0}\textrm{C}/(mol/kg)\times \frac{\frac{2.2g}{M}}{0.0167}mol/kg

so, M = 679 g/mol

4 0
3 years ago
Does alcohol affect enveloped or naked viruses more
slega [8]

Answer:

the protein capsid of naked  viruses is less susceptible to environmental .  condition

Explanation:

because the envelop is made in part of phospholipids. once the envelop is lysed ,the virus loses its functiovnal receptors and still able to infect susceptible cells.

7 0
2 years ago
What features did you use to classify igneous rocks as extrusive or intrusive ?
umka21 [38]

Answer: Igneous rocks may be simply classified according to their chemical/mineral composition as felsic, intermediate, mafic, and ultramafic, and by texture or grain size: intrusive rocks are course grained (all crystals are visible to the naked eye) while extrusive rocks may be fine-grained (microscopic crystals) or glass.

Explanation: Hope this helped! :)

6 0
3 years ago
Read 2 more answers
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