A chemist dissolves 239 mg of pure potassium hydroxide in enough water to make up of solution. Calculate the pH of the solution.
(The temperature of the solution is .) Round your answer to significant decimal places.
1 answer:
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Answer:
T = 3206.89 K
Explanation:
Given that,
Number of moles, n = 1.9 moles
Pressure, P = 5 atm
Volume, V = 100 L
We need to find the temperature of the gas. Let the temperature is T. We know that,
PV = nRT
Where
R is gas constant, R = 0.08206 L-atm/mol-K
Put all the values,
So, the temperature of the gas is 3206.89 K.
% mass of a solution is the mass of the solute present per 100 g of solution. It can be calculated using the formula,
Mass of solute = 4.92 g
Mass of solvent, water = 347 g
Total mass of solution = 347 g + 4.92 g = 351.92 g
Mass % of the solute =
Therefore, the weight/weight % = 1.398 %