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Vika [28.1K]
3 years ago
14

The function f(h)=2d+4.3 relates the h (height) of the water in a fountain in feet to the d diameter of the pipe carrying the wa

ter. find the height of the water when the pipe has a diameter of 1.5 inches. answer
Mathematics
1 answer:
Vesna [10]3 years ago
7 0
F(1.5) = 2*1.5 +4.3 = 7.3

..................................,.
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Find three consecutive integers whose sum is negative 21
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-6,-7, and -8, this is more of a guess and check question

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What is 4[2(21-17)+3]
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To solve this problem, we should understand how order of operations works. Perhaps the best way to show you this would be solving the problem with all of the work clearly labeled?

=4[2(21-17)+3]    Original Problem
=4[2(4)+3]           Solved the Parentheses
=4[8+3]                Multiplied the 2 and 4
=4[11]                   Added the 8 and 3
=44                       Multiplied the 4 and 11

An easy way to remember this is PEMDAS, which is an acronym for Parentheses, Exponents, Multiplication/Division, and Addition/Subtraction. Although it will not apply in this scenario (because we have brackets), it will come in handy for many others like this.

Using all of the information above, we can conclude that this expression equals 4.  

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3 years ago
Reflect the given preimage over y=−1 followed by y=−7. Find the new coordinates. What one transformation is this double reflecti
fenix001 [56]

Answer:

Reflecting over y = -1 line:

A'(8, -10)

B'(10, -8)

C'(2, -4)

Reflecting over y = -7 line:

A''(8, -4)

B'(10, -6)

C''(2, -10)

Step-by-step explanation:

Reflect the given preimage over y=−1 followed

by y=−7. Find the new coordinates. What one transformation is this double reflection the same as? (Note: when you are reflecting over a y= line, the x-values of the preimage will remain the same and you will be changing the y-values)

The coordinates of the preimage are:

A(8,8)

B(10,6)

C(2,2)

Answer: Reflecting over y = -1:

If a point is reflected over a y line, the x values remain the same while the y values change.

For point A(8, 8): The y distance between the y = - 1 line and point A is 9 units. (8- (-1)). If point A is reflected, the y value would be 9 units below the y = -1 line, i.e the new y coordinate would be at -10 (-1-9)

The new coordinate is at A'(8, -10)

For point B(10, 6): The y distance between the y = - 1 line and point B is 7 units. (6- (-1)). If point B is reflected, the y value would be 7 units below the y = -1 line, i.e the new y coordinate would be at -8 (-1-7)

The new coordinate is at B'(10, -8)

For point C(2, 2): The y distance between the y = - 1 line and point C is 3 units. (2- (-1)). If point C is reflected, the y value would be 3 units below the y = -1 line, i.e the new y coordinate would be at -4 (-1-3)

The new coordinate is at C'(2, -4)

Reflecting over y = -7 line:

For point A'(8, -10): The y distance between the y = - 7 line and point A' is 3 units. (-7- (-10)). If point A' is reflected, the y value would be 3 units above the y = -7 line, i.e the new y coordinate would be at -4 (-7+3)

The new coordinate is at A''(8, -4)

For point B'(10, -8): The y distance between the y = - 7 line and point B' is 1 units. (-7- (-8)). If point B' is reflected, the y value would be 1 units above the y = -7 line, i.e the new y coordinate would be at -6 (-7 + 1)

The new coordinate is at B'(10, -6)

For point C'(2, -4): The y distance between the y = - 7 line and point C' is 3 units. (-4- (-7)). If point C' is reflected, the y value would be 3 units below the y = -7 line, i.e the new y coordinate would be at -10 (-7-3)

The new coordinate is at C''(2, -10)

We can also see that h= −7−(−1)=−6. We know that two reflections is the same as a translation of 2h  units down. So 2(−6) is a translation of −12 units down.

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3 years ago
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