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Keith_Richards [23]
3 years ago
14

C=3.95p what’s the slope

Mathematics
1 answer:
sladkih [1.3K]3 years ago
6 0

Answer:

3.95

Step-by-step explanation:

The slope is the same thing as the 'rate of change'. Both of them tell you how fast or slow the number (C) will increase or decrease.

The number (C) changes depending on what 'p' is. Since 'p' is attached to 3.95, meaning they will multiply, 3.95 is the slope.

If you learn linear equations:

Linear (straight line) graphs can be written y = mx + b.

"x" and "y" are points on the graph.

<u>"m is the slope (attached to 'x').</u>

"b" is the y-intercept (when the graph hits the y-axis.

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Step-by-step explanation:

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3 years ago
Assume that it costs Apple approximately E(x) 25,600 + 100x + 0.012 dollars to manufacture x 32GB iPods in a day. (a) The averag
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Answer:

(a)C'(x)=\dfrac{x^2-2560000}{x^2}

(b)x=1600, Minimum Average Cost Per iPod=$132

(c)C''(x)=\dfrac{5120000}{x^3}

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

Step-by-step explanation:

Given that it costs Apple approximately $ C(x) to manufacture x 32GB iPods in a day, where:

C(x)=25,600+100x+0.01x^2

(a)The average cost per iPod when they manufacture x iPods in a day is given by:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}

The average cost per iPod is therefore:

C'(x)=\dfrac{x^2-2560000}{x^2}

(b)To minimize average cost of x iPods per day, we set the average cost per iPod=0 and solve for x.

C'(x)=\dfrac{x^2-2560000}{x^2}=0\\x^2-2560000=0\\x^2=2560000\\x=\sqrt{2560000}=1600

The resulting minimum average cost (at x=1600) is given as:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}\\\dfrac{25,600+100(1600)+0.01(1600)^2}{1600}\\=\$132

<u>Second derivative test</u>

(c)The answer above is a critical point for the average cost function. To show it is a minimum, we calculate the second derivative of the average cost function.

C''(x)=\dfrac{5120000}{x^3}

At the critical point,  x=1600

C''(1600)=\dfrac{5120000}{1600^3}=0.00125

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

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