(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
<u>Answer:</u>
The system of equations are
x + y = 2600 …….equation (1)
and, 6x + 5y = 13700 ……equation (2)
<u>Explanation:</u>
Let x = amount of sales of phone;
y = amount of sales of computer
For phone, 6% of sales is 6% of x, or 6% * x = 0.06x.
Similarly for computer,
5% of y = 0.05y
Given the total sales; x + y = 2600
And commission; 0.06x + 0.05y = 137; or 6x + 5y = 13700
Therefore the system of equations are
x + y = 2600 …….equation (1)
6 x + 5 y = 13700 ……equation (2)
We have two right triangles and three different rectangles.
The formula of an area of a right triangle:
l₁, l₂ - legs
We have l₁ = 20cm and l₂ = 21cm. Substitute:
The formula of an area of a rectangle:
l - length
w - width
We have:
rectangle #1: l = 22cm, w = 29cm
rectangle #2: l = 22cm, w = 21cm
rectangle #3: l = 22cm, w = 20cm
The total Surface Area of the triangular prism:
