Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
Answer:
4d+24
Step-by-step explanation:
The distributive property says that 4(d+6)=4d+(4)(6)
which simplifies to 4d+24
(I hope that's what you needed, please lmk if you needed more than just simplifying.)
<span>A word problem that can be modeled by addition of two negative numbers integers is given as followed.
Evans and Irvin are standing at the same spot. Evans took 7 steps backwards and another 7 steps backward, what is the current position of Evans relative to where Irvin is standing?
To solve the above, we note that Evans </span><span>took 7 steps backwards and another 7 steps backward, thus his current position relative to Irvin is given by (-7) + (-7) = -7 - 7 = -14.
Therefore, Evans is 14 steps backwards relative to where Irvin is standing.
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