Complete the square to find the y-value for the minimum value of the function-f(x)=x^2-8x+28
1 answer:
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Answer:
12
Step-by-step explanation:
The square can be completed by adding and subtracting the square of half the linear term's coefficient.
f(x) = x^2 -8x +(-8/2)^2 +28 -(-8/2)^2
f(x) = (x^2 -8x +16) +(28 -16)
f(x) = (x -4)^2 +12
The minimum value of the function is 12, when the squared term is zero.
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Answer:
A.
Statement: ∠6 ≅ ∠14
Reason: For parallel lines cut by a transversal, corresponding angles are congruent.
Step-by-step explanation:
In the figure attached, a plot of the problem is shown.
Given p || q and r is a transversal which cut p and q, then ∠1 ≅ ∠5 and ∠2 ≅ ∠6.
Given r || s and q is a transversal which cut r and s, then ∠6 ≅ ∠14 and ∠8 ≅ ∠16.
From the picture we see that ∠1 and ∠2 are supplementary, that is, their addition is equal to 180º. ∠2 ≅ ∠6 and ∠6 ≅ ∠14, then ∠2 ≅ ∠14, in consequence ∠1 and ∠14 are supplementary.
