Complete the square to find the y-value for the minimum value of the function-f(x)=x^2-8x+28
1 answer:
9514 1404 393
Answer:
12
Step-by-step explanation:
The square can be completed by adding and subtracting the square of half the linear term's coefficient.
f(x) = x^2 -8x +(-8/2)^2 +28 -(-8/2)^2
f(x) = (x^2 -8x +16) +(28 -16)
f(x) = (x -4)^2 +12
The minimum value of the function is 12, when the squared term is zero.
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9514 1404 393
Answer:
(f/g)(8) = -104/41
Step-by-step explanation:
Fill in the value for x and do the arithmetic.
f(8) = 3 -2·8 = 3 -16 = -13
g(8) = 1/8 +5 = (1+40)/8 = 41/8
Then the ratio is ...
(f/g)(8) = f(8)/g(8) = -13/(41/8) = -13(8)/41
(f/g)(8) = -104/41
