Complete the square to find the y-value for the minimum value of the function-f(x)=x^2-8x+28
1 answer:
9514 1404 393
Answer:
12
Step-by-step explanation:
The square can be completed by adding and subtracting the square of half the linear term's coefficient.
f(x) = x^2 -8x +(-8/2)^2 +28 -(-8/2)^2
f(x) = (x^2 -8x +16) +(28 -16)
f(x) = (x -4)^2 +12
The minimum value of the function is 12, when the squared term is zero.
You might be interested in
So the answer is choice D. You can check this by differentiating the right hand side and you'll get x^3 back again.
This answer can be found by using the power rule for integrals. That rule is