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3 years ago

Helppp.....Which one of the following statements does not describe gold?

Chemistry

1 answer:

Mariulka [41]3 years ago

4 0

Answer: D. It reacts with oxygen in the presence of moist air.

Explanation:

The element Gold, does not react with oxygen,hence it is not affected by corrosion,neither does it rust.

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HEY ITS E AGAIN HELP ITS A TEST

valentina_108 [34]

Answer:

i am not 100% shure but the wind speed has little to effect it so a and b are not the answer so i think the answer is D

Explanation:if i got this wrong im sorry it has bin a wile since i answered a question like this.

4 0

3 years ago

A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

Ede4ka [16]

<u>Answer:</u> The mass of glucose in final solution is 1.085 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL$

Putting values in above equation, we get:

$0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g$

Hence, the mass of glucose in final solution is 1.085 grams

4 0

3 years ago

A(n)

alex41 [277]

It should be scientific law since a hypothesis is like a prediction and a theory could be used to explain something although it might not be true. There’s many theories just to explain one thing. So it should be scientific law

8 0

3 years ago

The controlled Release of nuclear energy in a creator is accomplished by: allowing the critical mass of fuel to react . Controll

pishuonlain [190]

Answer:

If a chain reaction takes place, the amount of energy released would increase exponentially, so in order to control the energy release, fission must be controlled without controlling a chain reaction, so the third option is correct.

Hope this helps!

Explanation:

4 0

3 years ago

ASAPPP. Describe how you could determine the specific heat of a sample of a solid substance. You may

Allushta [10]

Answer:

I would use calorimetric to determine the specific heat and I would measure the mass of a sample

Explanation:

I would use calorimetry to determine the specific heat.

I would measure the mass of a sample of the substance.

I would heat the substance to a known temperature.

I would place the heated substance into a coffee-cup calorimeter containing a known mass of water with a known initial temperature.

I would wait for the temperature to equilibrate, then calculate temperature change.

I would use the temperature change of water to determine the amount of energy absorbed.

I would use the amount of energy lost by substance, mass, and temperature change to calculate specific heat.

8 0

3 years ago