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3 years ago

Which of the following is most critical for our study of outter space

1 answer:

6 0

In my opinion, the answer would be d: a universal language. D would technically be more important because there are so many foreign scientific companies and to get the information we need to study the universe, we should communicate and give eachother what we have of our resources as we work for it.

You might be interested in

Before a cell enters mitosis, what happens to the genetic information in that cell?

trasher [3.6K]

Before a cell could undergo to the process of mitosis, the cell will have to undergo first to the stage of interphase. Where it will need to pass though three stages where it will prepare before it could undergo to cell division. The cell will most likely pass to G1, S and G2 phase for it to be checked and prepared before it passes through the mitosis.

4 0

3 years ago

When the system pressures are lower than the pressure in the refrigerant tank, such as when the system has just been evacuated o

steposvetlana [31]

Answer: True

Explanation:

It should be noted that when refrigerant is added in vapor form to the operating refrigeration system, then the addition of the refrigerant should be to the low-pressure side of the refrigeration system.

Furthermore, when system pressures are lower than the pressure in the refrigerant tank as stated in the question, then the refrigerant can be added to both the high and low pressure sides of the system.

Therefore, the correct option is true.

5 0

3 years ago

Three crates with various contents are pulled by a force F pull = 3615 N across a horizontal, frictionless roller‑conveyor syste

Dmitry_Shevchenko [17]

Answer:

m1=914.9kg

m2=604.9kg

m3=864.75kg

Explanation

I think we are suppose to find the mass of the crate.

The effective force that moves the body in positive x direction is 3615N

ΣFx = Σma

Then Fx=3615N

Then the masses be m1, m2 and m3

Then,

ΣF = Σ(ma)

3615=(m1+m2+m3)a

Given that a=1.516

The masses are

m1+m2+m3=, 2384.56. Equation 1

Between mass 1 and mass 2 is, F12=1387.

The effective force that pull mass 1 is 1387.

F12=m1 ×a

Therefore,

m1=F12/a

m1=1387/1.516

m1=914.9kg.

The effective force that pulls crate 1 and crate 2 is F23

F23=(m1+m2)a

Therefore

2304=(m1+m2)a

Therefore, since a=1.516

m1+m2=2304/1.516

m1+m2=1519.8kg

Since m1=914.9kg

So, m2=1519.8-m1

m2=1519.8-914.9

m2=604.9kg

Also from equation 1

m1+m2+m3=2384.56

Since m1=914.9kg and m2=604.9kg

Then, m3=2384.56-604.9-914.9

m3=864.75kg

3 0

3 years ago

A substance has density ρ, mass m, and volume V. If the volume is tripled, what is the new mass?

Igoryamba

Since the density of the substance is ρ (rho),

==> every cm³ of this substance has ρ grams of mass.

Then

==> V cm³ of it has ρV grams of mass. That's ' m '.

and

==> 3V cm³ of it has 3ρV grams of mass. That's ' <em>3m</em> '.

6 0

4 years ago

By what factor must we increase the amplitude of vibration of an object at the end of a spring in order to double its maximum sp

strojnjashka [21]

Answer:

$A'=2A$

Explanation:

According to the law of conservation of energy, the total energy of the system can be expresed as the sum of the potential energy and kinetic energy:

$E=U+K=\frac{kA^2}{2}\\E=\frac{kx^2}{2}+\frac{mv^2}{2}=\frac{kA^2}{2}$

When the spring is in its equilibrium position, that is $x=0$ , the object speed its maximum. So, we have:

$\frac{k(0)^2}{2}+\frac{mv_{max}^2}{2}=\frac{kA^2}{2}\\A^2=\frac{mv_{max}^2}{k}\\A=\sqrt{\frac{mv_{max}^2}{k}}$

In order to double its maximum speed, that is $v'{max}=2v_{max}$ . We have:

$A'=\sqrt{\frac{m(v'_{max})^2}{k}}\\A'=\sqrt{\frac{m(2v_{max})^2}{k}}\\A'=\sqrt{\frac{4mv_{max}^2}{k}}\\A'=2\sqrt{\frac{mv_{max}^2}{k}}\\A'=2A$

6 0

3 years ago