Explanation:
Given that,
Object distance u= -110 cm
Image distance v= 55 cm
We need to calculate the focal length for diverging lens
Using formula of lens

Put the value into the formula


The focal length of the diverging lens is 36.6 cm.
Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.
Here, The object distance is again the same.
We need to calculate the image distance for converging lens
Using formula of lens

Here, focal length is positive for converging lens



The distance of the image is 54.85 cm from converging lens.
Hence, This is the required solution.
The time period resulting in oscillations will be 1.986 seconds.
<h3>What is the period of oscillation?</h3>
The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.
The time period of the oscillation is;

Hence the time period resulting oscillations will be 1.986 seconds.
To learn more about the time period of oscillation refer to the link;
brainly.com/question/20070798
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First do 1.6 m (how far he jumps) 9.8 m/s (what gravity is measured at) then times 2
= 31.36
Sq root = 5.6
Answer:
25 to the right
Explanation:
there you go friend your awsome
Answer:
the results will be the same.it may be