1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WINSTONCH [101]
2 years ago
7

Before a cell enters mitosis, what happens to the genetic information in that cell?

Physics
1 answer:
trasher [3.6K]2 years ago
4 0
Before a cell could undergo to the process of mitosis, the cell will have to undergo first to the stage of interphase. Where it will need to pass though three stages where it will prepare before it could undergo to cell division. The cell will most likely pass to G1, S and G2 phase for it to be checked and prepared before it passes through the mitosis.
You might be interested in
An object weighs 60.0 kg on the surface of the earth. How much does it weigh 4R from the surface? (5R from the center)
Alecsey [184]
"60 kg" is not a weight.  It's a mass, and it's always the same
no matter where the object goes.

The weight of the object is   

                                 (mass) x (gravity in the place where the object is) .

On the surface of the Earth,

                   Weight = (60 kg) x (9.8 m/s²)

                                =      588 Newtons.

Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to  5R  from the center, the gravity out there is

                    (1R/5R)²  =  (1/5)²  =  1/25  =  0.04 of its value on the surface.

The object's weight would also be 0.04 of its weight on the surface.

                 (0.04) x (588 Newtons)  =  23.52 Newtons.

Again, the object's mass is still 60 kg out there.
___________________________________________

If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink. 
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
6 0
2 years ago
How would you find the total energy stored in the
likoan [24]

Answer:

The energy of the capacitors connected in parallel is 0.27 J

Given:

C = 2.0\micro F = 2.0\times 10^{- 6} F

C' = 4.0\micro F = 4.0\times 10^{- 6} F

Potential difference, V = 300 V

Solution:

Now, we know that the equivalent capacitance of the two parallel connected capacitors is given by:

C_{eq} = C + C' = 2.0 + 4.0 = 6.0\micro F = 6.0\times 10^{- 6} F

The energy of the capacitor, E is given by;

E = \frac{1}{2}C_{eq}V^{2}

E = \frac{1}{2}\times 6.0\times 10^{- 6}\times 300^{2} = 0.27 J

6 0
2 years ago
In hydrogen, the transition from level 2 to level 1 has a rest wavelength of 121.6 nm.1).Find the speed for a star in which this
soldier1979 [14.2K]

Answer:

1). v = - 2960526m/s

2). Toward us

3). v = - 493421m/s

4). Toward us

5). v = 1480263m/s

6).  Away from us

7). v = 3207236m/s

8). Away from us

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when it is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest is 121.6 nm (\lambda_{0} = 121.6nm)

Redshift: \lambda_{measured} > \lambda_{0}

Blueshift: \lambda_{measured} < \lambda_{0}

Then, for this particular case it is gotten:

Star 1: \lambda_{measured} = 120.4nm

Star 2: \lambda_{measured} = 121.4nm

Star 3: \lambda_{measured} = 122.2nm

Star 4: \lambda_{measured} = 122.9nm

Star 1:

Blueshift: 120.4nm < 121.6nm

Toward us

Star 2:

Blueshift: 121.4nm < 121.6nm

Toward us

Star 3:

Redshift: 122.2nm > 121.6nm

Away from us

Star 4:

Redshift: 122.9nm > 121.6nm

Away from us

Due to that shift the velocity of the star can be determine by means of Doppler velocity.

v = c\frac{\Delta \lambda}{\lambda_{0}}  (1)

Where \Delta \lambda is the wavelength shift, \lambda_{0} is the wavelength at rest, v is the velocity of the source and c is the speed of light.

v = c(\frac{\lambda_{measured}- \lambda_{0}}{\lambda_{0}}) (2)

<em>Case for star 1 \lambda_{measured} = 120.4 nm:</em>

<em></em>

v = (3x10^{8}m/s)(\frac{120.4nm-121.6nm}{121.6nm})

v = - 2960526m/s

Notice that the negative velocity means that is approaching to the observer.

<em>Case for star 2 \lambda_{measured} = 121.4 nm:</em>

v = (3x10^{8}m/s)(\frac{121.4nm-121.6nm}{121.6nm})

v = - 493421m/s

<em>Case for star 3 \lambda_{measured} = 122.2 nm:</em>

v = (3x10^{8}m/s)(\frac{122.2nm-121.6nm}{121.6nm})

v = 1480263m/s

<em>Case for star 4 \lambda_{measured} = 122.9 nm:</em>

v = (3x10^{8}m/s)(\frac{122.9nm-121.6nm}{121.6nm})

v = 3207236m/s

4 0
3 years ago
A 5 μF capacitor is connected to a 12 V battery. The charge on each plate of the capacitor is:
ziro4ka [17]
1 farad = 1 coulomb/volt

5 μF = 5 x 10⁻⁶ coulomb/volt

        = 60 x 10⁻⁶ coulomb / 12 volts

The charge is 60 x 10⁻⁶ coulombs = 6 x 10⁻⁵  (choice-A) 


3 0
3 years ago
1. If you push a 40.0kg mass object with a force of 145.ON, what will be the object's
horrorfan [7]

Newton said . . . F = m a

Divide each side by  m . . .  a = F / m

Acceleration = (force) / (mass)

Acceleration = (145.O N) / (40.0 kg)

<em>Acceleration = 3.625 m/s²</em>

4 0
2 years ago
Other questions:
  • A person travels by car from one city to another with different constant speeds between pair of cities. She drives for 36 min at
    14·1 answer
  • Which one of the following statements concerning momentum is true? Group of answer choices Momentum is a force. Momentum is a sc
    9·1 answer
  • Which of the following is not an appropriate category of childrens book to include in the early childhood classroom?
    5·2 answers
  • Which of the following is true statement about isotopes?
    9·2 answers
  • Blood is 92% water. Blood is
    7·1 answer
  • What is the speed that the Earth orbits the Sun?
    14·1 answer
  • A 20" round duct is 275' in length. The duct is carrying 2,900 CFM at a friction loss of 0.12 inches WG per 100 feet.
    14·1 answer
  • WILL GIVE BRAINLIST QUICK!!! How does biodiversity support different varieties of species? (please put short answer)
    7·1 answer
  • A steel playground slide is 5.25 m long and is raised 2.75 m on one end. A 45.0 kg child slides down from the top starting at re
    9·1 answer
  • An object with a mass of m = 122 kg is suspended by a rope from the end of a uniform boom with a mass of M = 74.9 kg and a lengt
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!