Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Answer:
5.4 hr i think
Step-by-step explanation:
It can be a fraction, a decimal, a mixed number, or any irrational number.
Answer:
y=4x-3
then add 3 to each side to get: y+3=4x.
Next, just divide both sides by 4 to get x = (y+3)\div4.
Answer:
The bottom point is at (-1, 1) the right point is at (6,-2) and the left point is at (-5,4)
Step-by-step explanation: