Two football players collide head-on in midair while chasing a pass. The first player has a 110 kg mass and an initial velocity
1 answer:
Answer:
v = 0.012 m/s
Explanation:
This is a problem of momnetun, to solve it we must define a system that includes both players. In this case the forces during the crash are internal forces and the momentum is preserved
Initial
p₀ = m₁ v₁₀ + m₂ v₂₀
Final
= (m₁ + m₂) v
Because the two players are united
p₀ =
m₁ v₁₀ + m₂ v₂₀ = = (m₁ + m₂) v
v = (m₁ v₁₀ + m₂ v₂₀) / (m₁ + m₂)
let's calculate
v = (110 4.20 - 135 3.40) / (110 + 135)
v = 3/245
v = 0.012 m/s
The positive sign indicates that they move to the right
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Answer:
option (c)
Explanation:
Fundamental frequency of segment A = f
Second harmonic frequency of B = fundamental frequency of A .
Tension in both the wires is same and the mass density is also same as the wires are identical.
fundamental frequency of wire A is given by
.... (1)
Second harmonic of B is given by
.... (2)
Equation (1) is equal to equation (2), we get
So, LB = 2 L
Thus, the length of wire segment B is 2 times the length of wire segment A.
Answer:
The impact occured at a distance of 2478.585 meters from the person.
Explanation:
(After some research on web, we conclude that problem is not incomplete) The element "Part A" may lead to the false idea that question is incomplete. Correct form is presented below:
<em>A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 6.4 seconds apart. How far away did the impact occur? (Sound speed in the air: 343 meters per second, sound speed in concrete: 3000 meters per second)</em>
Sound is a manifestation of mechanical waves, which needs a medium to propagate themselves. Depending on the material, sound will take more or less time to travel a given distance. From statement, we know this time difference between air and concrete (), in seconds:
(1)
Where:
- Time spent by the sound in concrete, in seconds.
- Time spent by the sound in the air, in seconds.
By suposing that sound travels the same distance and at constant speed in both materials, we have the following expression:
(2)
Where:
- Speed of the sound in concrete, in meters per second.
- Speed of the sound in the air, in meters per second.
- Distance traveled by the sound, in meters.
If we know that ,
and
, then the distance travelled by the sound is:
The impact occured at a distance of 2478.585 meters from the person.
Answer:
The value is
Explanation:
From the question we are told that
The radius of the tires is
The angular acceleration is
Generally the linear acceleration is mathematically represented as
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