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2 years ago

6

Liquid pressure does not depend on

1 answer:

STALIN [3.7K]2 years ago

8 0

Answer:

it's answer is density of object

Explanation:

it depend on

depth

density of water

gravity

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Why dont you fall through walls when you lean against them? provide a scientific explanation to explain your answer.

kondaur [170]

Answer:

That's why if you lean against the wall, you don't just fall through it. The wall pushes back on you as hard as you push on it, and you and the wall stay in place. If you throw something, you put more force behind it than just leaning on it, so it pushes back with more force.

Explanation:

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3 years ago

Why does it take more force to move a heavy box up a ramp than to move the same box down the ramp?

ICE Princess25 [194]

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2 years ago

A tennis ball is tossed upwards into the air with an initial velocity of +5m/s, how much time does it take for the tennis ball t

Sever21 [200]

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2 years ago

What is the potential difference when the current in a circuit is 5mA and resistance is 30 Ohms

Mashcka [7]

<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf• \: The \: current \: in \: a \: circuit \: is \: 5 \: amps. \: and \: resistance \: is \: 30 \: Ohms.$

$\\$

<h2> $\bf{ \underline{To \: Find :- }}$ </h2>

$\sf{• \: The \: Potential \: Difference. }$

$\\$

$\huge\bf{ \underline{ Solution:- }}$

$\sf According \: to \: the \: question,$

$\sf• \: Current \: (I) = 5 \: Amps.$

$\sf• \: Resistance \: (R) = 30 \: Ω$

$\sf{Potential \: difference \: means \: Voltage \: ( V).}$

$\sf{We \: know \: that, }$

$\bf \red{ \bigstar{ \: V = IR }}$

$\rightarrow \sf V =5 \times 30$

$\rightarrow \sf V =150$

$\\$

$\sf \purple{Therefore, \: the \: potential \: difference \: is \: 150 \: v \: .}$

4 0

3 years ago

A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi

Mamont248 [21]

Answer:

$a=368.97\ m/s^2$

Explanation:

Given that,

Initial angular velocity, $\omega=0$

Acceleration of the wheel, $\alpha =7\ rad/s^2$

Rotation, $\theta=14\ rotation=14\times 2\pi =87.96\ rad$

Let t is the time. Using second equation of kinematics can be calculated using time.

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s$

Let $\omega_f$ is the final angular velocity and a is the radial component of acceleration.

$\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s$

Radial component of acceleration,

$a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2$

So, the required acceleration on the edge of the wheel is $368.97\ m/s^2$ .

6 0

3 years ago